Answer:
Step-by-step explanation:
To find the matrix A, took all the numeric coefficient of the variables, the first column is for x, the second column for y, the third column for z and the last column for w:
![A=\left[\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%261%262%262%5C%5C-7%26-3%265%26-8%5C%5C4%261%261%261%5C%5C3%267%26-1%261%5Cend%7Barray%7D%5Cright%5D)
And the vector B is formed with the solution of each equation of the system:![b=\left[\begin{array}{c}3\\-3\\6\\1\end{array}\right]](https://tex.z-dn.net/?f=b%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D3%5C%5C-3%5C%5C6%5C%5C1%5Cend%7Barray%7D%5Cright%5D)
To apply the Cramer's rule, take the matrix A and replace the column assigned to the variable that you need to solve with the vector b, in this case, that would be the second column. This new matrix is going to be called 
.
![A_{2}=\left[\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right]](https://tex.z-dn.net/?f=A_%7B2%7D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%263%262%262%5C%5C-7%26-3%265%26-8%5C%5C4%266%261%261%5C%5C3%261%26-1%261%5Cend%7Barray%7D%5Cright%5D)
The value of y using Cramer's rule is:
Find the value of the determinant of each matrix, and divide:
Answer: it’s either 5x^3 -4x^2-7x or
-3x^3-4x^2-7x
Step-by-step explanation:
i put it in my calculator
Three miles a day should be the correct answer
<h3>Answers:</h3><h3>x = 1 or x = 16</h3>
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Work Shown:
Draw out a rectangle that is 32 units wide horizontally and 8 units tall vertically.
Then draw out another rectangle that is 4 meters wide horizontally and x meters tall vertically.
The horizontal and vertical sides pair up to form these fractions: 32/4 and 8/x
Set the fractions equal to one another. Solve for x
32/4 = 8/x
32x = 8*4 ... cross multiply
32x = 32
x = 32/32 ... divide both sides by 32
x = 1
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Somewhere else on your paper, draw the same 32 by 8 rectangle to make 32 the horizontal component
Next to this rectangle, draw a rectangle that has x as the horizontal part and 4 as the vertical. Note the swap here.
We now have this equation to solve for
32/x = 8/4
once again, note the swap
Let's solve for x
32/x = 8/4
32*4 = 8*x
128 = 8x
8x = 128
x = 128/8
x = 16
Equation 4 is different <3
