B is the answer
i simplified the theorem, but i hope this makes sense!
Answer:
The last one (-1,5)
Step-by-step explanation:
From (0,0), the R coordinate is one to the left meaning the x is negative and five up which means the y is positive 5 so... (-1,5) is the new location of R.
Let h represent the height of the trapezoid, the perpendicular distance between AB and DC. Then the area of the trapezoid is
Area = (1/2)(AB + DC)·h
We are given a relationship between AB and DC, so we can write
Area = (1/2)(AB + AB/4)·h = (5/8)AB·h
The given dimensions let us determine the area of ∆BCE to be
Area ∆BCE = (1/2)(5 cm)(12 cm) = 30 cm²
The total area of the trapezoid is also the sum of the areas ...
Area = Area ∆BCE + Area ∆ABE + Area ∆DCE
Since AE = 1/3(AD), the perpendicular distance from E to AB will be h/3. The areas of the two smaller triangles can be computed as
Area ∆ABE = (1/2)(AB)·h/3 = (1/6)AB·h
Area ∆DCE = (1/2)(DC)·(2/3)h = (1/2)(AB/4)·(2/3)h = (1/12)AB·h
Putting all of the above into the equation for the total area of the trapezoid, we have
Area = (5/8)AB·h = 30 cm² + (1/6)AB·h + (1/12)AB·h
(5/8 -1/6 -1/12)AB·h = 30 cm²
AB·h = (30 cm²)/(3/8) = 80 cm²
Then the area of the trapezoid is
Area = (5/8)AB·h = (5/8)·80 cm² = 50 cm²
Answer: imma say A
Step-by-step explanation: sorry if wrong
Answer: 11
The code would print 11 as x=x-4 basically sets x to what x was and subtracts it by 4 which means 15 was its previous value and it takes 4 away from it so it is now 11. Then because the loop condition is x=11 the loop condition has been met and will now go and display x.
