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2 years ago

What is the slope of the line passing through the points (0,-5) and (4,2)

Mathematics

1 answer:

Vesna [10]2 years ago

7 0

Answer: 7/4.

Step-by-step explanation: To find the slope of a line, one must use the formula (y2-y1)/(x2-x1). In this case y2 is 2, y1 is -5, x2 is 4, and x1 is 0. We can plug this into the equation to get 7/4.

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PLEASE HELP ME W THIS QUESTION

snow_lady [41]

Answer:

Step-by-step explanation:

If the side of the shape is increased by 3/2 then the total distance around the shape will be 3/2 bigger.

Example: If the pentagon has side length 2 then it becomes 2*3/2 = 6/2 = 3.

The original perimeter was 2+2+2+2+2 = 10.

The new perimeter is 3+3+3+3+3 = 15.

Did you notice that $\frac{15}{10}=\frac{3}{2}$ ? J is correct.

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3 years ago

can somebody please write what are the rules for multiplying integers and the rules for dividing integers in a short answer?

arsen [322]

Answer:

Negative + Negative = Positive

Negative + Positive = Negative

Positive + Negative = Negative

Positive + Positive = Negative

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Step-by-step explanation:

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2 years ago

Select the best possible first step to solving the system by first eliminating the x variable. 3x − 9y = 6 2x − 11y = 6

Klio2033 [76]

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3 years ago

adults say that they have cheated on a test or exam before. You randomly select six adults. Find the probability that the number

VLD [36.1K]

Answer: a. 1/6. b. 2/3. c. 5/6

Step-by-step explanation:

Number of adults randomly selected= 6

a. Finding the probability of adults that have cheated on an examination before is exactly 4.

The numbers are 1, 2, 3, 4, 5 and 6.

Probability of chosen exactly 4 will be 1/6 since 4 can only occur once.

b. More than 2means 3,4, 5 and 6.

Probability that the number of adults that have cheated on a test or exam is more than 2 will be:

4/6 = 2/3

c. At most 5 means 1,2,3,4 or 5

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3 years ago

A foreign student club lists as its members 2 Canadians, 3 Japanese, 5 Italians, and 2 Germans. If a committee of 4 is selected

Fittoniya [83]

Answer:

(a) The probability that the members of the committee are chosen from all nationalities $=\frac{4}{33}$ =0.1212.

(b)The probability that all nationalities except Italian are represent is 0.04848.

Step-by-step explanation:

Hypergeometric Distribution:

Let $x_1$ , $x_2$ , $x_3$ and $x_4$ be four given positive integers and let $x_1+x_2+x_3+x_4= N$ .

A random variable X is said to have hypergeometric distribution with parameter $x_1$ , $x_2$ , $x_3$ , $x_4$ and n.

The probability mass function

$f(x_1,x_2.x_3,x_4;a_1,a_2,a_3,a_4;N,n)=\frac{\left(\begin{array}{c}x_1\\a_1\end{array}\right)\left(\begin{array}{c}x_2\\a_2\end{array}\right) \left(\begin{array}{c}x_3\\a_3\end{array}\right) \left(\begin{array}{c}x_4\\a_4\end{array}\right) }{\left(\begin{array}{c}N\\n\end{array}\right) }$

Here $a_1+a_2+a_3+a_4=n$

${\left(\begin{array}{c}x_1\\a_1\end{array}\right)=^{x_1}C_{a_1}= \frac{x_1!}{a_1!(x_1-a_1)!}$

Given that, a foreign club is made of 2 Canadian members, 3 Japanese members, 5 Italian members and 2 Germans members.

$x_1$ =2, $x_2$ =3, $x_3$ =5 and $x_4$ =2.

A committee is made of 4 member.

N=4

(a)

We need to find out the probability that the members of the committee are chosen from all nationalities.

$a_1$ =1, $a_2$ =1, $a_3$ =1 , $a_4$ =1, n=4

The required probability is

$=\frac{\left(\begin{array}{c}2\\1\end{array}\right)\left(\begin{array}{c}3\\1\end{array}\right) \left(\begin{array}{c}5\\1\end{array}\right) \left(\begin{array}{c}2\\1\end{array}\right) }{\left(\begin{array}{c}12\\4\end{array}\right) }$

$=\frac{2\times 3\times 5\times 2}{495}$

$=\frac{4}{33}$

=0.1212

(b)

Now we find out the probability that all nationalities except Italian.

So, we need to find out,

$P(a_1=2,a_2=1,a_3=0,a_4=1)+P(a_1=1,a_2=2,a_3=0,a_4=1)+P(a_1=1,a_2=1,a_3=0,a_4=2)$

$=\frac{\left(\begin{array}{c}2\\2\end{array}\right)\left(\begin{array}{c}3\\1\end{array}\right) \left(\begin{array}{c}5\\0\end{array}\right) \left(\begin{array}{c}2\\1\end{array}\right) }{\left(\begin{array}{c}12\\4\end{array}\right) }+\frac{\left(\begin{array}{c}2\\1\end{array}\right)\left(\begin{array}{c}3\\2\end{array}\right) \left(\begin{array}{c}5\\0\end{array}\right) \left(\begin{array}{c}2\\1\end{array}\right) }{\left(\begin{array}{c}12\\4\end{array}\right) }$ $+\frac{\left(\begin{array}{c}2\\1\end{array}\right)\left(\begin{array}{c}3\\1\end{array}\right) \left(\begin{array}{c}5\\0\end{array}\right) \left(\begin{array}{c}2\\2\end{array}\right) }{\left(\begin{array}{c}12\\4\end{array}\right) }$

$=\frac{1\times 3\times 1\times 2}{495}+\frac{2\times 3\times 1\times 2}{495}+\frac{2\times 3\times 1\times 1}{495}$

$=\frac{6+12+6}{495}$

$=\frac{8}{165}$

=0.04848

The probability that all nationalities except Italian are represent is 0.04848.

6 0

3 years ago

What is the slope of the line passing through the points (0,-5) and (4,2)​

What is the slope of the line passing through the points (0,-5) and (4,2)