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Mathematics

1 answer:

Annette [7]3 years ago

8 0

Part A: The answer is B.
As vertically opposite angles are equal
x+10=4x-35
10=3x-35
45=3x
x=15

Part B: The answer is D.
We'll substitute in the value of X in one equation.
x+10
=15+10
=25
As the two angles are equal bot must be 25 degrees.

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What’s the answer to m/3-2m/5=1/5

natta225 [31]

Answer:

m = - 3

Step-by-step explanation:

$\frac{m}{3} - \frac{2m}{5} = \frac{1}{5}$

It is much easier to work with whole numbers, compared to fractions, hence one should remove the denominator of the fraction. This can be done by multiplying by the LCM (least common multiple). In this case, it is fairly obvious that the LCM of 3 and 5 is 15. Therefore multiply the entire equation by 15.

$15*\frac{m}{3} - 15*\frac{2m}{5}=15*\frac{1}{5}$

Simplify

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3 years ago

The value of a dirtbike decreases by 15% each year if you purchase this dirtbike today for $500 to the nearest dollar how much w

ArbitrLikvidat [17]

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3 years ago

4. Find the sum of all the numbers from 100 to 199 that are not divisible by 13.

Ierofanga [76]

There are 100 numbers in the range 100-199. Find the smallest and largest multiple of 13 in this range. We have

104 = 8•13

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so there are 15 - 8 + 1 = 8 multiples of 13 between 100 and 199.

Then the sum we want is

$\displaystyle \sum_{k=100}^{199} k - \sum_{\ell=8}^{15}13\ell$

or equivalently,

(100 + 101 + 102 + … + 199) - 13 (8 + 9 + … + 15)

To compute these sums, recall the following formula:

$\displaystyle \sum_{i=1}^n i = 1 + 2 + 3 + \cdots + n = \frac{n(n+1)}2$

Then

$\displaystyle \sum_{k=100}^{199} k = \sum_{k=1}^{199} k - \sum_{k=1}^{99} k = \frac{199\cdot200}2 - \frac{99\cdot100}2 = 14,950$

and

$\displaystyle \sum_{\ell=8}^{15} 13\ell = 13 \left(\sum_{\ell=1}^{15} \ell - \sum_{\ell=1}^7 \ell\right) = 13 \left(\frac{15\cdot16}2 - \frac{7\cdot8}2\right) = 1,196$