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3 years ago

Plzz help i hav a test after i need the answer quick plzz.

Mathematics

1 answer:

Katen [24]3 years ago

5 0

Answer:Oop

Step-by-step explanation:

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Solve for x: 7+4x=13+x

Mnenie [13.5K]

$7+4x=13+x \\\\4x-x=13-7 \\\\3x=6 \\\\\boxed{x=\frac{6}{3}=2}$

3 0

2 years ago

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Write the equation in standard form for the circle with center (0, – 10) and radius 6.

Artemon [7]

Answer:

Equation of circle in standard form with centre (0, – 10) and radius 6. $\mathbf{x^2+(y+10)^2=36}$

Step-by-step explanation:

We need to write equation of circle in standard form with centre (0, – 10) and radius 6.

The equation of circle is: $(x-h)^2+(y-k)^2=r^2$

where (h,k) is centre of circle and r is radius

We are given centre (0,-10) so, h=0, k=-10 and radius r = 6

Putting values and finding equation:

$(x-h)^2+(y-k)^2=r^2\\(x-0)^2+(y-(-10))^2=(6)^2\\x^2+(y+10)^2=36$

So, equation of circle in standard form with centre (0, – 10) and radius 6. $\mathbf{x^2+(y+10)^2=36}$

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3 years ago

50pts help! consider this quadratic equation. 2x^2-1=3x+4 Which equation correctly applies to the quadratic formula?

eduard

Step-by-step explanation:

im not going to go in to detail but the answer is c

7 0

3 years ago

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Convert 28 inches to ___ feet and inches.<br><br> ?????????????

musickatia [10]

Answer:

2 feet and 33 inches

Step-by-step explanation:

You just divide by 12 since

12 inches = 1 foot

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2 years ago

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(1 point) Linear System - Three Variables Solve the following system of equations using Gaussian elimination method. If there ar

EastWind [94]

Answer:

$x=\frac{-363}{70}$ ≈ -5.1857

$y=\frac{-192}{35}$ ≈ -5.4857

$z=\frac{313}{84}$ ≈ 3.7262

Step-by-step explanation:

Rewrite the equation system as:

$6x+8y=-75$

$-3x+6y+6z=5$

$2x-9y=39$

Now, write the system in its augmented matrix form:

$\left[\begin{array}{cccc}6&8&0&-75\\-3&6&6&5\\2&-9&0&39\end{array}\right]$

applying row reduction process to its associated augmented matrix:

Swap R1 and R3, and then Swap R1 and R2:

$\left[\begin{array}{cccc}-3&6&6&5\\2&-9&0&39\\6&8&0&-75\end{array}\right]$

R3+2R1

$\left[\begin{array}{cccc}-3&6&6&5\\2&-9&0&39\\0&20&12&-65\end{array}\right]$

3R2+2R1

$\left[\begin{array}{cccc}-3&6&6&5\\0&-15&12&127\\0&20&12&-65\end{array}\right]$

15R3+20R2

$\left[\begin{array}{cccc}-3&6&6&5\\0&-15&12&127\\0&0&420&1565\end{array}\right]$

Now we have a simplified system:

$-3x+6y+6z=5\\0-15y+12z=127\\0+0+420z=1565$

$-3x+6y+6z=5\hspace{5 mm}(1)\\0-15y+12z=127\hspace{3 mm}(2)\\0+0+420z=1565\hspace{3 mm}(3)$

From (3):

$z=\frac{313}{84}$ (4)

Replacing (4) in (2)

$y=\frac{-192}{35}$ (5)

Finally replacing (5) and (4) in (1)

$x=\frac{-363}{70}$

7 0

3 years ago