Answer:
Plants are restrictive to flow of eroding agents, bind soil in their roots.
Step-by-step explanation:
Soil Erosion is the wearing away of the topmost fertile layer of soil. Topsoil gets eroded mainly due to wind, water agents.
Plants help to prevent soil from erosion in following ways :
- Plants act as restriction to the speed of air & water, which are the main soil erosion agents. It also lets rain water get soaked into the ground water.
- Plants roots also bind the soil tightly, & make soil stronger to be eroded by erosive agents - water, air. Eg : Shrubs , trees, grass & ground are important soil erosion preventive plants, because of their extensive root systems.
Hello!
To find the y-values of the given ordered pairs, substitute the x-values into the equation, y = log₂ x.
y = log₂ 1/2, y = -1
y = log₂ 1, y = 0
y = log₂ 2, y = 1
y = log₂ 4, y = 2
y = log₂ 8, y = 3
y = log₂ 16, y = 4
Therefore, the ordered pairs of y = log₂ x is: {(1/2, -1), (1, 0), (2, 1), (4, 2), (8, 3), (16, 4)}.
NO. Sine is opposite/hypotenuse, so the answer should be 24/25
The horizontal distance from the helicopter to the landing pad is 1658.81 feet
<em><u>Solution:</u></em>
The figure is attached below
Triangle ABC is a rightangled triangle
A helicopter is flying at point A and landing pad is at point c
Angle of depression of the helicopter is 37 degrees so angle of elevation of this helicopter from landing pad will be same as 37 degrees
The helicopter is 1250 feet from the ground
Therefore, AB = 1250 feet
To find: horizontal distance from the helicopter to the landing pad
BC is the horizontal distance from the helicopter to the landing pad
BC = ?
By the definition of tan,


Thus the horizontal distance from the helicopter to the landing pad is 1658.81 feet
At first we need to know how to find the distance between two parallel lines
The parallel lines which have the same slope
If we have two parallel lines ⇒ y₁ = mx + c₁ and y₂ = mx + c₂
So, the distance between y₁ and y₂ = d =

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Part (1):=======
<span>The distance between the lines
</span>
<span>
Y₁ = 3x + 10 and Y₂ = 3x - 20</span>
∴ m = 3 , c₁ = 10 and c₂ = -20
∴ d =

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Part (2):=======
<span>The distance between the lines
</span>
Y₁ = <span>3/2 x + 3/2</span> and Y₂ = <span>3/2 x - 5</span>
∴ m = 3/2 = 1.5 , c₁ = 3/2 = 1.5 and c₂ = -5
∴ d =