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natima [27]
3 years ago
12

How do you do 43.552 divided by 39.4?

Mathematics
1 answer:
alexira [117]3 years ago
8 0
43.552 ÷ 39.4 = 1.105380711

I don't know if you have to do any roundings for your problem, though.
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3cis(5pi/4) in polar form
madreJ [45]
Rectangular form:
z = -2.1213203-2.1213203i

Angle notation (phasor):
z = 3 ∠ -135°

Polar form:
z = 3 × (cos (-135°) + i sin (-135°))

Exponential form:
z = 3 × ei (-0.75) = 3 × ei (-3π/4)

Polar coordinates:
r = |z| = 3 ... magnitude (modulus, absolute value)
θ = arg z = -2.3561945 rad = -135° = -0.75π = -3π/4 rad ... angle (argument or phase)

Cartesian coordinates:
Cartesian form of imaginary number: z = -2.1213203-2.1213203i
Real part: x = Re z = -2.121
Imaginary part: y = Im z = -2.12132034
8 0
3 years ago
If M is the set of all square numbers less than 80 and N is the set of all non-negative even numbers that are under 30, Write th
Nat2105 [25]

Answer:

Step-by-step explanation:

All square numbers are numbers formed by squaring a single number. If M is the set of all square numbers less than 80, then

M = (4, 9, 16, 25, 49, 64)

Even numbers are numbers that are divisible by 2 without remainder.

If N is the set of all non-negative even numbers that are under 30, then

N = (2, 4, 6, 8 ,10, 12, 14, 16,18,20, 22, 24, 26,28)

It will not include 30 because we want even numbers under 30

8 0
3 years ago
How far from an airport can an airplane fly and return in 8 hours, if it's outgoing speed is 160 km per hour and it's returning
PilotLPTM [1.2K]
<span>speed = distance/time
total time is 8 hours

outgoing speed is 160 km per hour, 
so time = d/160

</span><span>returning speed is 240 km per hour,
so time = d/240

 d/160 + d/240 = 8

3d/480 + 2d/480 = 8
5d/480 = 8
5d =480 (8)
5d = 3840
d=3840/5
d=768

answer: so the distance is 768 km</span>
4 0
3 years ago
Read 2 more answers
What is the value of 1.2^2
sveticcg [70]
Value of 1.2^2=1.44
value of 2^3+17-3*4=8+17-12=13
value of 9^2/3^3= 81/27=3
7 0
3 years ago
Select all the correct graphs.<br> Choose the graphs that indicate equations with no solution.
Natali [406]

Answer:

The first and last graph.

General Formulas and Concepts:

<u>Algebra I</u>

  • Solving systems of equations graphically

Step-by-step explanation:

In order for a systems of equations to have a solution set, the 2 graphs must intersect at at least 1 point. Here, we see that graphs 1 and 5 do not intersect each other at all.

Therefore, the rest of the graphs have solutions and #1 and #5 do no have any solutions.

3 0
3 years ago
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