3 sides of square is 3*12=36 cm
perimeter for the full circle is 2 * pi * radius
which is =2 * 22/7 * 12 =75.43 cm
so 360° =75.43 cm
for 150° = 75.43/360 *150 =31.43
all together =36 +31.43 =67.43 cm
First one:
cos(A)=AC/AB=3/4.24
cos(B)=BC/AB=3/4.24
Cos(A)/cos(B)=AC/AB / (BC/AB) = AC/AB * AB/BC = AC/BC=3/3=1
Second one:
To solve this problem, we have to ASSUME AFE is a straight line, i.e. angle EFB is 90 degrees. (this is not explicitly given).
If that's the case, AE is a transversal of parallel lines AB and DE.
And Angle A is congruent to angle E (alternate interior angles).
Therefore sin(A)=sin(E)=0.5
Hi there!

Recall the volume of a pyramid is:
V = 1/3(bh)
We are given the volume and side length of the base. Find the area of the base:
A = s²
A = (5xy²)² = 25x²y⁴
Plug in the solved for base:
125x³y³ = 1/3(25x²y⁴)h
To isolate for h, begin by multiplying both sides by 3:
375x³y³ = (25x²y⁴)h
Divide both sides by 25x²y⁴. Use the following exponent property:
xᵃ / xᵇ = xᵃ⁻ᵇ
Thus:
375x³y³ / 25x²4⁴ = 15x/y.
The height must be equal to:

Answer:
The center of the circle is midpoint of the diameter:
The radius is equal the distance between C and Q:
An equation of a circle:
(x - a)² + (y - b)² = r²
(a; b) - a coordinates of a center
r - a radius
r = √65; (-3; 2) ⇒ a = -3 and b = 2
subtitute
(x - (-3))² + (y - 2)² = (√65)²
Answer:
the center: (-3; 2)
the radius: √65
the equation of the circle: (x + 3)² + (y - 2)² = 65