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balandron [24]
3 years ago
5

The combined volume of three pools at a water park is 1.35 · 10^4 gallons. The water park plans to install a new pool with a vol

ume of 3,500 gallons. What will be the total volume of all the pools at the water park after the new pool is installed?
Mathematics
1 answer:
loris [4]3 years ago
7 0

Answer:

16500 gallons

Step-by-step explanation:

Due to:

(1.35)*(10^4) = 13500

then, with the new pool with 3500 gallons, the total volumen will be:

Vt = 13500 + 3500

Vt = 16500 gallons

Best regards

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<u>Annotation</u>
General formula for distance-time-velocity relationship is as following
d = v × t
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The velocity of the second car will be v₂, the time is 2 hours, the distance will be d₂.


One of them traveling 5 miles per hour faster than the others. That means the velocity of the first car is 5 miles per hour more than the velocity of the second car.
v₁ = v₂ + 5  (first equation)

The distance of the two cars after two hours will be 262 miles apart. Because they go to opposite direction, we could write it as below.
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Plug the d-v-t relationship to the second equation
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v₁ × 2 + v₂ × 2 = 262
2v₁ + 2v₂ = 262

Plug the v₁ as  (v₂+5) from the first equation
2v₁ + 2v₂ = 262
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2v₂ + 10 + 2v₂ = 262
4v₂ + 10 = 262
4v₂ = 252
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v₂ = 63
The second car is 63 mph fast.

Find the velocity of the first car, use the first equation
v₁ = v₂ + 5
v₁ = 63 + 5
v₁ = 68
The first car is 68 mph fast.

Answer
\boxed{\boxed{ v_{1}=68mph} }
\boxed{\boxed{ v_{2}=63mph} }
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