Answer:
Yes, I can reject the null hypothesis with 95% confidence.
Step-by-step explanation:
Critical value t(63) = 1.99
p-value = 0.03
Confidence level (C) = 95% = 0.95
Significance level = 1 - C = 1 - 0.95 = 0.05
Conclusion:
Reject the null hypothesis because the p-value 0.03 is less than the significance level 0.05.
I think it is $30 since it has the highest probability.
reduce the index of the radical and exponent with 3, rhen you get your answer, 6
The difference between 10, 17 and 24 is 7, so we can write 7n
To get from 7 to 10 you add 3.
This can be written as 7n+3
Substitute 46 into n
7(46)+3
=325
I hope this helps.
Please mark me brainliest:)
