Answer:
Let O be the center of a circle whose radius is r cm , in which AB= 14 cm long
cord is at a distanceof 24 cm from O. Draw a perpendicular OD on AB , thus ,
OD= 24 cm.
In right angled triangle. ODB
OB^2 = OD^2+ DB^2
r^2 =(24)^2+(AB/2)^2 = 576+(14/2)^2
r^2 = 576+ 49=625
r = √625. =25 cm. Answer.
Answer:
m=6/7
Step-by-step explanation:
So if p then q
the converse is if q then p
so
if x is odd then 2x+1 is odd
converse is
if 2x+1 is odd, then x is odd
4th option
Answer:
(-1.1, 0.9)
Step-by-step explanation:
So if it is 3x^2+4x=2 then
set one side to zero
subtract 2 from both sides
3x^2+4x-2=0
this is not factorable by normal means so use quadratic formula which is if you have the equation in ax^2+bx+c=0 form you can solve for x if you put it into this equation quadratic formula

so if you were to input it into this equation you would get
a=3
b=4
c=-2
the solution is

the answer is C