Answer:

Step-by-step explanation:
![-4x^2+11x-6=-(4x^2-11x+6)=-(4x^2-8x-3x+6)\\\\=-\left[4x(x-2)-3(x-2)]=-(x-2)(4x-3)=(-4x+3)(x-2)](https://tex.z-dn.net/?f=-4x%5E2%2B11x-6%3D-%284x%5E2-11x%2B6%29%3D-%284x%5E2-8x-3x%2B6%29%5C%5C%5C%5C%3D-%5Cleft%5B4x%28x-2%29-3%28x-2%29%5D%3D-%28x-2%29%284x-3%29%3D%28-4x%2B3%29%28x-2%29)
Answer:
- The length = x = 15 units
- The width = x-5 = 10 units
Step-by-step explanation:
Let 'x' be the length of a rectangle
As the width of a rectangle is 5 units less than the length.
so
width of rectangle will be = w = x - 5 units
Area = 150 square units
Using the formula
Area = length × width



Subtract 50 from both sides



if



As length can not be negative. so
x = 15 units
Hence,
The length = x = 15 units
The width = x-5 = 15-5 = 10 units
Apply lg on both sides.
lg7^x^2 = lg9^x
Bring the power forward.
x^2lg7 = xlg9
x^2/x = lg9/lg7
x = lg9/lg7 = 1.13
Answer: D. Divide 5 by 1,200
Step-by-step explanation:
I know the answer
I think it is C)
I’m really sorry if I’m wrong.