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vitfil [10]
3 years ago
12

Kimmy has 47 ft.² of cement blocks each square block has size 1 foot long what is the greatest perimeter of a rectangle that she

can make with the cement blocks
Mathematics
1 answer:
blagie [28]3 years ago
3 0

Answer:

The larges perimeter she can make becomes is 96 ft

Step-by-step explanation:

Here we note that the available brick is 47 ft²

Therefore, she has 47 square cement blocks

Let the length of the sides of the rectangle with the most perimeter be x and y

Then 2·x + 2·y = 47 which is not possible because 47 is a prime number

Hence we have the possible sides of the rectangle is a single line of square blocks such that

x × y  = 47 ft² where y = 1 hence x = 47

The larges perimeter she can make becomes, 2 × (1 + 47) = 96 ft.

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The answer is -6. Thought there is a chance I am wrong. Need an explanation?
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3 years ago
Find the distance from the point (1,4) to the line y = 1/3x - 3
Troyanec [42]

Answer:

Step-by-step explanation:

If I'm not mistaken, and I very well could be, this is a calculus problem(?). In order to find the distance without calculus you'd need a point on the given line to use to find the distance in the distance formula. But you don't have a point on the given line, so we can find the shortest distance between the point (1, 4) and the given line using the derivative of the polynomial formed when using the distance formula.

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} and we have the x and y for x2 (or x1...it doesn't matter which you choose to fill in):

d=\sqrt{(1-x)^2+(4-y)^2}

but what we find is that we have too many unknowns here, namely, the distance, the x coordinate, and the y coordinate. So we can replace the y coordinate with what y is equal to in terms of the linear equation:

d=\sqrt{(1-x)^2+(4-\frac{1}{3}x-3)^2 } and simplify:

d=\sqrt{(1-x)^2+(7-\frac{1}{3}x)^2 }

. No we'll expand each binomial by squaring:

d=\sqrt{(1-2x+x^2)+(49-\frac{14}{3}x+\frac{1}{9}x^2)  }

.  Combining like terms gives us

d=\sqrt{\frac{10}{9}x^2-\frac{20}{3}x+50  }

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d=\sqrt{(\frac{10}{9})(3)^2-(\frac{20}{3})(3)+50   }

which simplifies down, finally, to

x ≈ 6.325 units

8 0
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