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V125BC [204]
3 years ago
8

Find the circumference of a circle with an area of 676pi

Mathematics
2 answers:
saveliy_v [14]3 years ago
6 0

Answer:

The circumference of the circle is 52π

Step-by-step explanation:

To solve this exercise we first have to calculate the radius of the circle, for this we will use the formula of area of ​​a circle and we will clear the radius

a = area = 676π

r = radius

a = π * r²

we clear r

r = √(a/π)

now we replace the known values

r =  √(676π/π)

r = √(676)

r = 26

now we use the formula to calculate the circumference of a circle

c = π * 2r

c = π * 2 *  26

c = 52π

The circumference of the circle is 52π

aniked [119]3 years ago
5 0

Answer:

area =676π

area=πrsq.=676π

then pie cut to pie

and rsq. =676

and 676is the root of 26

circumference of circle is 2πr

r=26

2×22/7×26

then answer is 163.4

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Determine whether the statements in (a) and (b) are logically equivalent.
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The two statements are logically equivalent.

Step-by-step explanation:

Let X be the statement that Bob is a double math and computer science major.

Y be the statement that Ann is a maths major.

Z be the statement that Ann is a double maths and computer science major.

The two statements written in terms of X, Y and Z now

a. Bob is a double math and computer science major and Ann is a math major, but Ann is not a double math and computer science major.

(x and y) and not z

b. It is not the case that both Bob and Ann are double math and computer science majors, but it is the case that Ann is a math major and Bob is a double math and computer science major.

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Noting that for logical statements,

Negation is represented by ~

And is represented by conjunction sign Λ

Or is represented by disjunction sign V

(x and y) and not z

(x Λ y) Λ (~z)

not (x and z) and (x and y)

~(x Λ z) Λ (x Λ y)

We can then simplify the second statement to obtain the first statement and prove the equivalence of both sides

~(x Λ z) Λ (x Λ y)

Using DE MORGAN'S theory, ~(x Λ z) = (~x) V (~z)

~(x Λ z) Λ (x Λ y) = ((~x) V (~z)) Λ (x Λ y)

Then applying the distributive law to the expression, we can open the bracket up

((~x) V (~z)) Λ (x Λ y)

= ((~x) Λ (x Λ y)) V ((~z) Λ (x Λ y))

Opening the first bracket up further

((~x) Λ (x Λ y)) V ((~z) Λ (x Λ y))

= ((~x) Λ x) Λ y) V ((~z) Λ (x Λ y))

The NEGATION law shows that (~x Λ x) = c (where c is a negation law parameter for when two opposite statements are combined in this manner, it works like a 0 in operation)

((~x) Λ x) Λ y) V ((~z) Λ (x Λ y))

= (c Λ y) V ((~z) Λ (x Λ y))

But (c Λ y) = (y Λ c) = c (according to the UNIVERSALLY BOUND law, see how c works like a 0 now?)

(c Λ y) V ((~z) Λ (x Λ y))

= c V ((~z) Λ (x Λ y))

= ((~z) Λ (x Λ y)) V c (commutative)

And one of the foremost IDENTITY laws is that (any statement) V c = c

((~z) Λ (x Λ y)) V c

= ((~z) Λ (x Λ y))

= (x Λ y) Λ (~z)

Which is the same as the first statement!

PROVED!!!

Hope this Helps!!!

5 0
3 years ago
Read 2 more answers
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