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4 years ago

At which value in the domain does f(x)=0 ?

Mathematics

2 answers:

lina2011 [118]4 years ago

5 0

f(x)=0

Domain are the set of x values

f(x)=0 , we find all the x values where y =0

At x intercepts y is always 0

so we find all the x intercepts.

x intercepts are the points where the graph crosses x axis

In the graph we can see that the graph crosses x axis at

-2.5 , -0.75 and 1

-2.5 , -0.75 and 1 are the domain where f(x)=0

Softa [21]4 years ago

4 0

The domain at which the function $f\left( x \right) = 0 \:{\text{is}\: \boxed{ - 2.5, - 0.75{\text{ and 1}}}.$

Further explanation:

Explanation:

The output values of the function are known as range and the input values on which function is defined is known as the domain of the function.

The x coordinates are the domain of the function and the y coordinates are the range of the function.

The one-to-one function is a function in which every value of the range has exactly one pre-image in the domain.

On x-axis the value of the function is zero.

From the graph it has been observed that the graph intersects the x-axis at $- 2.5, - 0.75{\text{ and 1}}.$

Therefore, the domain of the function for which its value is zero is $- 2.5, - 0.75{\text{ and 1}}.$

The domain at which the function $f\left( x \right) = 0\: {\text{is}\: \boxed{ - 2.5, - 0.75{\text{ and 1}}}.$

Learn more:

1. Learn more about inverse of the function brainly.com/question/1632445.

2. Learn more about range of the function brainly.com/question/1435353.

3. Learn more about range and domain of the function brainly.com/question/3412497.

Answer details:

Grade: Middle School

Subject: Mathematics

Chapter: Relation and Function

Keywords: domain, range, function, value, f(x)=0, x-values, y-values, x-intercepts, points, graph, x-axis, y-axis.

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Suppose we are interested in analyzing the weights of NFL players. We know that on average, NFL players weigh 247 pounds with a

tigry1 [53]

Answer:

$SE= \frac{\sigma}{\sqrt{n}} = \frac{47}{\sqrt{30}}= 8.58$

$ME= 1.64 *\frac{\sigma}{\sqrt{n}} = 1.64*\frac{47}{\sqrt{30}}= 14.073$

$\bar X - ME = 237- 14.073 = 222.927$

$\bar X + ME = 237+ 14.073 = 251.073$

$n=(\frac{1.640(47)}{5})^2 =237.65 \approx 238$

So the answer for this case would be n=238 rounded up to the nearest integer

Null hypothesis: $\mu \geq 247$

Alternative hypothesis: $\mu$

$z=\frac{237-247}{\frac{47}{\sqrt{30}}}=-1.165$

$p_v =P(z$

If we compare the p value and the significance level given $\alpha=0.1$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can't conclude that the true mean is lower than 247 at 10% of significance.

Step-by-step explanation:

For this case we have the following data given:

$\bar X =237$ represent the sample mean

$\sigma = 47$ represent the population deviation

$n =30$ represent the sample size selected

$\mu_0 = 247$ represent the value that we want to test.

The standard error for this case is given by:

$SE= \frac{\sigma}{\sqrt{n}} = \frac{47}{\sqrt{30}}= 8.58$

For the 90% confidence the value of the significance is given by $\alpha=1-0.9 = 0.1$ and $\alpha/2 = 0.05$ so we can find in the normal standard distribution a quantile that accumulates 0.05 of the area on each tail and we got:

$z_{\alpha/2}= 1.64$

And the margin of error would be:

$ME= 1.64 *\frac{\sigma}{\sqrt{n}} = 1.64*\frac{47}{\sqrt{30}}= 14.073$

The confidence interval for this case would be given by:

$\bar X - ME = 237- 14.073 = 222.927$

$\bar X + ME = 237+ 14.073 = 251.073$

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

And on this case we have that ME =5 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

Replacing into formula (b) we got:

$n=(\frac{1.640(47)}{5})^2 =237.65 \approx 238$

So the answer for this case would be n=238 rounded up to the nearest integer

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the true mean is lower than 247 pounds, the system of hypothesis would be:

Null hypothesis: $\mu \geq 247$

Alternative hypothesis: $\mu$

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{237-247}{\frac{47}{\sqrt{30}}}=-1.165$

P-value

Since is a left tailed test the p value would be:

$p_v =P(z$

Conclusion

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MaRussiya [10]

Answer:

f(x) = x - 3

Step-by-step explanation:

y = mx + b

first let's find b, the y-intercept

based on the graph, the y-intercept is (0,-3), so b = -3

immediately, we can eliminate f(x) = 3 - x and f(x) = -3x

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