Answer:]
At least 75% of the eruptions lasted between 1.24 and 5.6 minutes.
Step-by-step explanation:
We are given the following information in the question:
n = 32
Mean = 3.42
According to Chebyshev's rule:
At least , percent of data lies within , where s is the standadrd deviation of the data and is the mean of data.
For k = 2, we have
75% of data lies within the range of
Thus, at least 75% of the eruptions lasted between 1.24 and 5.6 minutes.
Well it would be C! so 78-74=4 so they are counting by 4's and 86+4=90 :33
2^10=1024
(a^m)^n=a^(m*n)
------------------
(2^(10))^(-1/5)
=2^(-10/5)
=2^(-2)
=1/4 (As the inverse of 2^2 is 1/4)
Brainliest of I helped : )
Here: Remember f(x) is the same thing as y.
Quadratic functions are y=x^2.
So you could literally add anything to it and make it another function. E.g. f(x)=x^2 + 1
You could just keep adding another value to the second term like x^2 + 2.
But if you want functions here you go:
x^2 -3x -4
x^2 +9x +8
x^2
x^2 +1
x^2 -3x -10
x^2 + 2x
2x^2
3x^2
4x^2
How do you graph them? Easy just choose an x value, like 0 or 1 or 7 or -5, and plug it into the equation. If you had f(x)=x^2 then it's just 5^2, 25. So when x is 5, f(x) [y is f(x)] is 25. Likewise you would plug it into 2x^2 and get 2 (5^2). When x is 5, f(x) is 50.... 2(25)= 50