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Vaselesa [24]
4 years ago
9

What is the solution set for the inequality? -6x+9>7x+74

Mathematics
1 answer:
Nesterboy [21]4 years ago
5 0

Answer:

Step-by-step explanation:

- 6x + 9 > 7x + 74

Treat them as being equal first.

Subtract 9 from both sides.

- 6x + 9 - 9 > 7x + 74 - 9

- 6x > 7x + 65

Subtract 7x from each side

- 6x - 7x > 7x - 7x + 65

- 13x > 65

Divide each side by -13

- 13x / -13  > 65 / -13

x < -5

So x hust be smaller than -5 meaning -6 works but -4 doesn't.

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The are of square frame is 55 square inches. find length of one side frame explain​
dangina [55]

Answer:

\sqrt {55} inches

Step-by-step explanation:

Let x inches be the length of one side of the frame. The frame is the square, so all sides have the same lengths.

Use formula A=x^2\ in^2 connecting the area of the square and the side length of the square.

Since the area ofthe square is 55 square inches, we have

x^2 =55\\ \\x=\sqrt {55}\ in

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3 years ago
Without using a calculator, choose the statement that the best describes the value of 24. Help me please...​
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Step-by-step explanation:

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Adelia drove from her house to Townsville one evening. Her distance was 180 miles. She left home at 6:27 and was at townsville a
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Step-by-step explanation:

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4 years ago
Which of the following equations is true for ATUX? I u A X t e tan X = O cos X = O sin X =23 O Sin X =​
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5 0
3 years ago
Read 2 more answers
Remember to show work and explain. Use the math font.
MrMuchimi

Answer:

\large\boxed{1.\ f^{-1}(x)=4\log(x\sqrt[4]2)}\\\\\boxed{2.\ f^{-1}(x)=\log(x^5+5)}\\\\\boxed{3.\ f^{-1}(x)=\sqrt{4^{x-1}}}

Step-by-step explanation:

\log_ab=c\iff a^c=b\\\\n\log_ab=\log_ab^n\\\\a^{\log_ab}=b\\\\\log_aa^n=n\\\\\log_{10}a=\log a\\=============================

1.\\y=\left(\dfrac{5^x}{2}\right)^\frac{1}{4}\\\\\text{Exchange x and y. Solve for y:}\\\\\left(\dfrac{5^y}{2}\right)^\frac{1}{4}=x\qquad\text{use}\ \left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}\\\\\dfrac{(5^y)^\frac{1}{4}}{2^\frac{1}{4}}=x\qquad\text{multiply both sides by }\ 2^\frac{1}{4}\\\\\left(5^y\right)^\frac{1}{4}=2^\frac{1}{4}x\qquad\text{use}\ (a^n)^m=a^{nm}\\\\5^{\frac{1}{4}y}=2^\frac{1}{4}x\qquad\log_5\ \text{of both sides}

\log_55^{\frac{1}{4}y}=\log_5\left(2^\frac{1}{4}x\right)\qquad\text{use}\ a^\frac{1}{n}=\sqrt[n]{a}\\\\\dfrac{1}{4}y=\log(x\sqrt[4]2)\qquad\text{multiply both sides by 4}\\\\y=4\log(x\sqrt[4]2)

--------------------------\\2.\\y=(10^x-5)^\frac{1}{5}\\\\\text{Exchange x and y. Solve for y:}\\\\(10^y-5)^\frac{1}{5}=x\qquad\text{5 power of both sides}\\\\\bigg[(10^y-5)^\frac{1}{5}\bigg]^5=x^5\qquad\text{use}\ (a^n)^m=a^{nm}\\\\(10^y-5)^{\frac{1}{5}\cdot5}=x^5\\\\10^y-5=x^5\qquad\text{add 5 to both sides}\\\\10^y=x^5+5\qquad\log\ \text{of both sides}\\\\\log10^y=\log(x^5+5)\Rightarrow y=\log(x^5+5)

--------------------------\\3.\\y=\log_4(4x^2)\\\\\text{Exchange x and y. Solve for y:}\\\\\log_4(4y^2)=x\Rightarrow4^{\log_4(4y^2)}=4^x\\\\4y^2=4^x\qquad\text{divide both sides by 4}\\\\y^2=\dfrac{4^x}{4}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\y^2=4^{x-1}\Rightarrow y=\sqrt{4^{x-1}}

6 0
4 years ago
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