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SOVA2 [1]
2 years ago
10

Please I need help anything

Mathematics
1 answer:
oee [108]2 years ago
4 0

Step-by-step explanation:

g(x)=5/4(2)^x

Make a table of points. Choose any 5.

X. Y

0 5/4. 5/4*2^0

1. 5/2. 5/4*2^1

2. 5. 5/4*2^2

3. 10. 5/4*2^3

4. 20. 5/4*2^4

The x, y table above are x, y coordinates to plot. To the right is just solving the equation with different values for the power of 2

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The cross-sectional areas of a right triangular prism and a right cylinder are congruent. The right triangular prism has a heigh
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Answer:

The correct answer is:

The volume of the triangular prism is equal to the volume of the cylinder

Step-by-step explanation:

Given that there are two figures

1. A right triangular prism and

2. Right cylinder

Area of cross section of prism is equal to Area of cross section of cylinder.

Let this value be <em>A</em>.

Also given that Height of prism = Height of cylinder = <em>6</em>

Volume of a prism is given as:

V_{Prism} = \text{Area of cross section} \times Height

V_{Prism} = A \times 6 ........ (1)

Cross section of cylinder is a circle.

<em>Area of circle</em> is given as: \pi r^{2}

Area of cross section, A = \pi r^{2}

Volume of cylinder is given as:

V_{Cylinder} = \pi r^{2} h\\\Rightarrow V_{Cylinder} = A \times h\\\Rightarrow V_{Cylinder} = A \times 6 ...... (2)

From equations (1) and (2) we can see that

V_{Prism}=V_{Cylinder}

Hence, the correct answer is:

Volume of prism is equal to the volume of cylinder.

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2 years ago
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<span>11 times the square root of 245 x to the third plus 9 times the square root of 45 x to the third is:
</span>11 \sqrt{245 x^{3} } +9 \sqrt{45 x^{3} } =11 \sqrt{245}  *\sqrt{ x^{3} } +9 \sqrt{45} *\sqrt{ x^{3} }= \\  \\ =11 \sqrt{5*49} * \sqrt{ x^{2} *x} +9 \sqrt{5*9} * \sqrt{ x^{2} *x}= \\  \\ =11* \sqrt{5}  * \sqrt{49} * \sqrt{ x^{2}} * \sqrt{x} +9* \sqrt{5} * \sqrt{9} * \sqrt{ x^{2} }* \sqrt{x} = \\  \\ &#10;=11* \sqrt{5} *7*x* \sqrt{x} +9* \sqrt{5} *3*x* \sqrt{x} = \\  \\ &#10;=77x* \sqrt{5*x} +27x* \sqrt{5*x}  = \\  \\ &#10;=77x \sqrt{5x} +27x \sqrt{5x} = \\  \\ &#10;=104x \sqrt{5x}
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