Do rise over run and it would be rise 1 run 4, 1/4
Answer:
29
Step-by-step explanation:
srry took a sec
The expression is equivalent to 
.
<h2 /><h2>Given that</h2>
Expression; 
<h3>We have to determine</h3>
Which expressions are equivalent to the given expression.
<h3>According to the question</h3>
Expression;
To solve the given expression follow all the steps given below.
By applying the distributive property of multiplication;
Then,
The equivalent expression is,
Hence, the expression is equivalent to .
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Answer:
no
Step-by-step explanation:
To determine if (1, 6) is a solution, substitute x = 1, y = 6 into the left side of both equations and if the value obtained equals the right side then it is a solution.
10(1) - 6 = 10 - 6 = 4 ≠ - 6
- 10(1) + 5(6) = - 10 + 30 = 20 ≠ 30
Then (1, 6 ) is not a solution to the system
If we draw the contingency table of x (vertical) against y (horiz.), we have a square.
For n=4, we have (legend: < : x<y = : x=y > : x>y
y 1 2 3 4
x
1 = < < <
2 > = < <
3 > > = <
4 > > > =
We see that there are n(n-1)/2 cases of x<y out of n^2.
Therefore,
p(x<y)=n(n-1)/(2n^2)=(n-1)/(2n)
However, if the sample space is continuous, it will be simply p(x<y)=1/2.
