Answer:
dy/dt = - (1/5) ft/s = - 0.2 ft/s
Step-by-step explanation:
Given
L = 5 ft
Qin = 25 ft³/s
Qout = 30 ft³/s
h = 10 ft
dy/dt = ?
We can apply the relation
ΔQ = Qint - Qout = 25 ft³/s - 30 ft³/s
⇒ ΔQ = - 5 ft³/s
Then we use the formula
Q = v*A
where Q = ΔQ, A = L² is the area of square base and v = dy/dt is the rate of change in the depth of the solution in the tank
⇒ ΔQ = (dy/dt)*L²
⇒ dy/dt = ΔQ/L²
⇒ dy/dt = (- 5 ft³/s)/(5 ft)²
⇒ dy/dt = - (1/5) ft/s = - 0.2 ft/s
Answer:
n * 2 - 3
Step-by-step explanation:
Let's say n is the number of minutes Mike ran then the expression would be
n * 2 - 3
-6 okokokokokokokokokokok
Answer:
<A = 27 degrees
Step-by-step explanation:
Since this is a right triangle, we can use trig functions
Tan A = opp side / adj side
Tan A = 2/4
Tan A = 1/2
Taking the inverse tan of each side
tan^-1 ( tan A) = tan ^-1 (1/2)
A =26.56505118
Rounding to the nearest degree
A = 27
A and C are complementary
B is supplementary
