All categories

3 years ago

What is the value of the expression? Drag and drop the answer into the box to match the expression. 0.3(1/4−1)+0.35

Mathematics

2 answers:

k0ka [10]3 years ago

6 0

Order of operations is parenthesis, exponents, multiplication or division, and then addition and subtraction.

So lets start with the parenthesis:

1/4 - 1

we have to do the division first so:

.25 - 1

now we subtract:

-.75

So our problem looks like this now:

.3 (-.75) + .35

Now we do the multiplication first again:

-.225 + .35

Finally the addition:

.125

Answer:

.125

Jobisdone [24]3 years ago

6 0

Answer:

Step-by-step explanation:

125

You might be interested in

Express number 9 as a unit rate, you can also round

Katena32 [7]

125/200= 0.625 cents

0.625 cents to the nearest cent= 0.63

The unit rate is 0.63 miles.

Hope this helps!

6 0

4 years ago

A movie theater is showing 1 musical and 7 other movies (8 movies in total). Each type of movie is equally likely to be chosen.

lukranit [14]

Answer:

125

Step-by-step explanation:

1,000/8 because all the outcomes are evenly likely

7 0

3 years ago

Solve 2k(-3k + 4) + 6(k2 + 10) =k(4k + 8) - 2k(2k + 5). Check your solution.

Artist 52 [7]

Answer:

$k=\frac{-52}{18} \approx -2.89$ (2dp)

Step-by-step explanation:

$2k(-3k + 4) + 6(k^2 + 10) =k(4k + 8) - 2k(2k + 5)$

Expand brackets:

$-6k^2+8k+6k^2+60=4k^2+8-4k^2-10k$

simplify:

$8k+60=8-10k$

Collect terms:

$18k=-52\\$

Rearrange for k:

$k=\frac{-52}{18}$

4 0

3 years ago

Triangle ABC is similar to Triangle XYZ. Solve for x and y

Pie

Yz =5
Xz= 7
Hope this helps!!!

6 0

3 years ago

The mean number of words per minute (WPM) read by sixth graders is 84 with a standard deviation of 15 WPM. If 188 sixth graders

Anna007 [38]

Answer:

0.1836 = 18.36% probability that the sample mean would differ from the population mean by greater than 1.46 WPM

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

The mean number of words per minute (WPM) read by sixth graders is 84 with a standard deviation of 15 WPM.

This means that $\mu = 84, \sigma = 15$

Sample of 188

This means that $n = 188, s = \frac{15}{\sqrt{188}}$

What is the probability that the sample mean would differ from the population mean by greater than 1.46 WPM?

Greater than 84 + 1.46 = 85.46 or less than 84 - 1.46 = 82.54. Since the normal distribution is symmetric, these probabilities are equal, so we find one of them and multiply by 2.

Probability is is less than 82.54.

P-value of Z when X = 82.54. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$