Answer:
I think its 12 to this question
Answer: 86
Step-by-step explanation:
Answer:
13.567%
Step-by-step explanation:
We solve the above question, using z score formula
z = (x-μ)/σ, where
x is the raw score = 23.1 ounces
μ is the population mean = 22.0 ounces
σ is the population standard deviation = 1.0 ounce
More than = Greater than with the sign = >
Hence, for x > 23.1 ounces
z = 23.1 - 22.0/1.0
= 1.1
Probability value from Z-Table:
P(x<23.1) = 0.86433
P(x>23.1) = 1 - P(x<23.1)
P(x>23.1) = 1 - 0.86433
P(x>23.1) = 0.13567
Converting to percentage
= 0.13567 × 100
= 13.567%
Therefore, the percentage of regulation basketballs that weigh more than 23.1 ounces is 13.567%
<h2>
Hello!</h2>
The answer is: 33.33%
<h2>Why?</h2>
Since we have the average number of accidents that occurs in 1 month, and it's equal to 3, we can calculate the probability of 1 accident occurs by dividing it into the average number of accidents, using the following formula:

Where,
Favorable outcomes are the occurrence of the event, for this case, it's equal to 1.
Outcomes are the possible occurrence of the event, for this case, it's equal to 3.
So, by substituting we have:


So, the probability will be equal to 33.33%
Have a nice day!