Answer:
Below.
Step-by-step explanation:
A linear function contains a variable of the first degree only - for example f(x) = 2x - 1 or f(z) = 3z.
So y = x + 5 is linear.
Answer:
<u>y = w and ΔABC ~ ΔCDE</u>
Step-by-step explanation:
Given sin(y°) = cos(x°)
So, ∠y + ∠x = 90° ⇒(1)
And as shown at the graph:
ΔABC is aright triangle at B
So, ∠y + ∠z = 90° ⇒(2)
From (1) and (2)
<u>∴ ∠x = ∠z </u>
ΔCDE is aright triangle at D
So, ∠x + ∠w = 90° ⇒(3)
From (1) and (3)
<u>∴ ∠y = ∠w</u>
So, for the triangles ΔABC and ΔCDE
- ∠A = ∠C ⇒ proved by ∠y = ∠w
- ∠B = ∠D ⇒ Given ∠B and ∠D are right angles.
- ∠C = ∠E ⇒ proved by ∠x = ∠z
So, from the previous ΔABC ~ ΔCDE by AAA postulate.
So, the answer is <u>y = w and ΔABC ~ ΔCDE</u>
the fraction 1/5 horizontally expands the graph and the constant 12 move up the graph because is a sum
so the right option is the last
D. The graph of f(x) is vertically compressed by a factor of 5 and
shifted 12 units up
Answer:
y = -2x + 3 is the required equation
Step-by-step explanation:
From the graph we will get two ordered pairs
If we see that When x=0 then y=3 and when x = 1 then y=1
Now from this we can find the slope of the Graph
So slope of graph = (y2 - y1) / (x2-x1)
=(1-3) / (1-0)
=-2
So
Slope = m = -2
Now the equation is
y = mx + b
We have to find the value of b
as we have two ordered pairs we can take any of it to find the value of b because line passes through those points
taking (0,3) as a point
y= mx + b
put values
3 = -2*(0) + b
so
b=3
Now the equation of the line in this form is
y = mx + b
which is
y = -2x + 3
Answer:
6
Step-by-step explanation:
The mode is the number which appears most often in a set of numbers in this case that would be 6 because it appears twice
