Answer:
1.36 for the first one
1.875 for the second one
1.3 repeating for the third one
0.5 repeating for the fourth one
0.3 for the fifth one
Step-by-step explanation:
Answer:
the amount of angle the hall is so prob like 5
Step-by-step explanation:
you provided insufficient details to answer
Answer:
4k^2 + 14k - 8
Step-by-step explanation:
If you have any questions about the way I solved it, don't hesitate to ask me in the comments below ÷)
Answer:
7.6 seconds
Step-by-step explanation:
To solve this problem we can use the following equation:
S = So + 113*t + at^2/2
Where S is the final position, So is the inicial position, Vo is the inicial speed, a is the acceleration and t is the time.
In this problem, we have that S = 0, So = 65, Vo = 113 and a = -32 ft/s2 (The acceleration of gravity)
So we have that:
0 = 65 + 113t - 16t2
16t2 - 113t - 65 = 0
Using Bhaskara's formula, we have:
Delta = 113^2 + 4*65*16 = 16929
sqrt(Delta) = 130.11
t = (113 + 130.11) / (2*16) = 7.597 seconds
Rounding to nearest tenth, we have t = 7.6 seconds
Just divide it by two. That just means half of 526, which is 263.
