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2 years ago

11

The value of a car depreciates by 15% each year. The value of the car when new is $14000. WHat will be the value of the car afte

r 1 year.

1 answer:

deff fn [24]2 years ago

6 0

Answer:

$11,900

Step-by-step explanation:

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EXPLAIN AND I WILL GIVE BRAINLIEST

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Answer:

(-3, 2)

Step-by-step explanation:

To find the coordinates of a point being reflected across the x-axis you need to use the rule (x, -y) on the point. Example: If the point was (4, 7) you would make the y value negative since it is positive, which would give you (4, -7) which is the point after being reflected across the x-axis. I know this one is for reflecting on the x-axis but for future problems if you want to reflect across the y-axis you do the same thing but with the x value, so (-x, y)

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2 years ago

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Figure ABCD is a trapezoid. Find

Rudiy27

Answer:

x = 3

Step-by-step explanation:

The midsegment is half the sum of the parallel bases, that is

$\frac{1}{2}$ (3x + 3 + 4x + 2) = 13

$\frac{1}{2}$ (7x + 5) = 13 ( multiply both sides by 2 )

7x + 5 = 26 ( subtract 5 from both sides )

7x = 21 ( divide both sides by 7 )

x = 3

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2 years ago

1. Look for a pattern in the first three equations. Then, fill in the missing numbers in the rest of the

Alla [95]

Answer:

1=1 times 2/2 1 + 2=2 times 3/2 1 +2+3=3 times 4/2 1+2+3+4=4 times 5/2 1+2+3+4+5=5 times 6/2

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2 years ago

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2 years ago

A group of three undergraduate and five graduate students are available to fill certain student government posts. If four studen

creativ13 [48]

Answer:

$Pr = 0.4286$

Step-by-step explanation:

Given

Let

$U \to\\$ Undergraduates

$G \to$ Graduates

So, we have:

$U = 3; G =5$ -- Total students

$r = 4$ --- students to select

Required

$P(U =2)$

From the question, we understand that 2 undergraduates are to be selected; This means that 2 graduates are to be selected.

First, we calculate the total possible selection (using combination)

$^nC_r = \frac{n!}{(n-r)!r!}$

So, we have:

$Total = ^{U + G}C_r$

$Total = ^{3 + 5}C_4$

$Total = ^8C_4$

$Total = \frac{8!}{(8-4)!4!}$

$Total = \frac{8!}{4!4!}$

Using a calculator, we have:

$Total = 70$

The number of ways of selecting 2 from 3 undergraduates is:

$U = ^3C_2$

$U = \frac{3!}{(3-2)!2!}$

$U = \frac{3!}{1!2!}$

$U = 3$

The number of ways of selecting 2 from 5 graduates is:

$G = ^5C_2$

$G = \frac{5!}{(5-2)!2!}$

$G = \frac{5!}{3!2!}$

$G =10$

So, the probability is:

$Pr = \frac{G * U}{Total}$

$Pr = \frac{10*3}{70}$

$Pr = \frac{30}{70}$

$Pr = 0.4286$

5 0

2 years ago