Answer:
1.5
Step-by-step explanation:
225° bisects Q III
315° bisects Q IV
-270° = 90°
405° = 45° bisects Q I
cos(225) sin(315) + sin( –270) tan(405) = ?
(-½√2)(-½√2) + 1(1) = ?
0.5 + 1 = 1.5
Answer:
it is the third option of g(x)=|x-1|+3x-1
the way I look at this is by visualizing the translations using the parent function of f(x)=|x|
the function moved up three and to the right by one which led to my conclusion
Answer:
4=4
Step-by-step explanation:
Answer:

Step-by-step explanation:
The given quadratic form is of the form
.
Where
.Every quadratic form of this kind can be written as

Observe that
is a symmetric matrix. So
is orthogonally diagonalizable, that is to say,
where
is an orthogonal matrix and
is a diagonal matrix.
In our case we have:

The eigenvalues of
are
.
Every symmetric matriz is orthogonally diagonalizable. Applying the process of diagonalization by an orthogonal matrix we have that:


Now, we have to do the change of variables
to obtain

Which can be written as:

Answer:
an increase then a pause then anotha increase
Step-by-step explanation: