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Alenkinab [10]
3 years ago
10

Aliyah I had some candy to give to her four children. she first took ten pieces for herself and then evenly divided the rest amo

ng her children. each child receive two pieces. with how many pieces did she start?
Mathematics
1 answer:
ozzi3 years ago
4 0
She started with 18 prices of candy
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The area of a rectangular bedroom is 240 square feet and the length is 16 feet what is the width
kirill [66]
1.)   240 divided by 16.
2.)   15
The width of the bedroom is 15 feet.

I hope this helps, please Brainliest me, and have a wonderful night! :D
8 0
3 years ago
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tarik starts a morning walk at 7:00 am. his distance, in miles, to the nearby grocery store after x hours is f(x)
Grace [21]

Total distance walked by Tarik is 0.75 miles according to the given equation.

What is equation?

In arithmetic, an equation could be a formula that expresses the equality of 2 expressions, by connecting them with the sign =.

Main body:

Given that

The expression that represents the Tarik's distance is

=>  f(x) = 3∣x−0.5∣

And also given that at 7.15 am he is some distance away from the store

Let Tarik is 'a' miles away from the store at 7.15 am

The time taken to walk 'a' miles = 7.15 - 7.00 = 15 minutes

As we know 60 minutes = 1 hr

=> 15 minutes = 15/60 = 0.25 hrs  

The given expression to find the Distance is

f(x) = 3 ∣x − 0.5∣    where x is number of hours

At x = 0.25

f(0.25) = 3 |0.25 - 0.5|

= 3 |- 0.25|

= 0.75 miles

Therefore,Tarik is 0.75 miles away from the store.

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8 0
1 year ago
170 is 1/10 of 17 true or false
Arisa [49]
I I'm guessing true if you don't think so then don't take my advice.
6 0
2 years ago
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R(r1+r2)=r1r2<br> How do I solve for r
Studentka2010 [4]
The answer is r = 0,3

7 0
3 years ago
What is the limit of f (×) as x approaches - infinty
tatyana61 [14]
If the degree of numerator and denominator are equal, then limit will be leading coefficient of numerator divided by the leading coefficient of denominator.

So then the limit would be 3/1 = 3.

Alternatively,

\displaystyle \lim_{x\to\infty}\dfrac{3x^2+6}{x^2-4}=\displaystyle \lim_{x\to\infty}\dfrac{3x^2+6}{x^2-4}\cdot\dfrac{1/x^2}{1/x^2}=\lim_{x\to\infty}\dfrac{3+\frac6{x^2}}{1-\frac4{x^2}} = \dfrac{3+0}{1-0}=\boxed{3}

Hope this helps.
5 0
3 years ago
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