Designs on business flyers should be based on the business' theme and the message that it wants to communicate. <span>A sale should have a design that would attract customers with the discounts they can avail with their purchases. </span><span>
</span>Texts, colors, lines, shapes, and images are the elements that should be figured out depending on the kind of communication that a business would want to share. <span>
</span><span>A sale flyer uses big text to emphasize discounts. Advertising products with amounts should require friendly designs with short and clear-cut messages. Colors can also drive customers and associate it with the kind of product. </span>
Answer:
1) List
2) Dictionary
3) Tuple
Explanation:
A list uses square brackets. It is used to store multiple items in just one variable. They are usually changeable and give room for duplicates. You use append to add to the collection.
A dictionary uses curly brackets. You use update to add to the collection. A dictionary is created by placing the elements in curly brackets and separating them with a comma. It is changeable and it does not give room for duplicates.
A tuple uses parentheses. You cannot change it once you create it. It is an ordered list of elements that is finite and can also store multiple items in one variable.
Answer:
bottom right
Explanation:
at least on windows it's bottom right
Answer:
import java.util.*;
public class MyClass {
public static void main(String args[]) {
Scanner input = new Scanner(System.in);
System.out.print("Input a word: ");
String userinput = input.nextLine();
for(int i =0;i<userinput.length();i+=2) {
System.out.print(userinput.charAt(i));
}
}
}
Explanation:
This line prompts user for input
System.out.print("Input a word: ");
This declares a string variable named userinput and also gets input from the user
String userinput = input.nextLine();
The following iterates through every other character of userinput from the first using iteration variable i and i is incremented by 2
for(int i =0;i<userinput.length();i+=2) {
This prints characters at i-th position
System.out.print(userinput.charAt(i));
Answer:
class OddNumber
{
public static void main(String args[])
{
int n = 1000; //Store 1000 in Variable n typed integer
System.out.print("Odd Numbers from 1 to 1000 are:"); // Print headline of output window
for (int i = 1; i <= n; i++) //For loop to go through each number till end
{
if (i % 2 != 0) //check if number is even or odd.Not divisible by 2 without reminder means it is odd number
{
System.out.print(i + " "); //print odd numbers
}
}
}
}
