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Airida [17]
4 years ago
15

Radar tracking station O is 40 km away from a ship at Point A. The ship travels east 45 km to point C at 30 km/h. How long will

the ship be on the radar with a 20 km radius?
Mathematics
1 answer:
RUDIKE [14]4 years ago
7 0
First, let's find the time where the ship arrives to point C
t=d/V, t= 45/30=1.5h
if the ship's departure time is at 1.5h, on the point C, let 's find its arrival to the point O, V=D/Dt,  Dt=tfinal-tinitial
Dt=D/V= 20/30=0.6h=t final -t initial, implies t final=0.6+t initial=0.6+1.5=2.1h

so the ship will be on the radar at 2.1h, 
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Answer:

\frac{2}{1}

Step-by-step explanation:

Each shape is 1 whole.

In the given image, there are 4 parts in each shape.

The shaded part in the first shape is 4.

The fraction of the shaded part in the first shape

                                            =\frac{Number of shaded part}{Total part of the fraction}=\frac{4}{4}

The shaded part in the second shape is 4.

The fraction of the shaded part in the second shape

                                           =\frac{Number of shaded part}{Total part of the fraction}=\frac{4}{4}

The shaded part of the model =\frac{4}{4}+\frac{4}{4}

                                                  =\frac{1}{1}+\frac{1}{1}

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Hence, the fraction represented by the shaded part of the model is \frac{2}{1}.

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3 years ago
Collins has a part-time job as a dog walker. The table below shows the amount of money Collins earned for different numbers of h
solmaris [256]

Answer:

Step-by-step explanation:

Part A:

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For 8 hours, he earns 8 hours * $6/hour = $48

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$35 - $30 = $5

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