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Airida [17]
4 years ago
15

Radar tracking station O is 40 km away from a ship at Point A. The ship travels east 45 km to point C at 30 km/h. How long will

the ship be on the radar with a 20 km radius?
Mathematics
1 answer:
RUDIKE [14]4 years ago
7 0
First, let's find the time where the ship arrives to point C
t=d/V, t= 45/30=1.5h
if the ship's departure time is at 1.5h, on the point C, let 's find its arrival to the point O, V=D/Dt,  Dt=tfinal-tinitial
Dt=D/V= 20/30=0.6h=t final -t initial, implies t final=0.6+t initial=0.6+1.5=2.1h

so the ship will be on the radar at 2.1h, 
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marusya05 [52]

Answer:

  (a)  A = 700×1.015^t

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Step-by-step explanation:

(a) Each year, the account value is multiplied by (1 + 1.5%) = 1.015. Repeated multiplication is signified using an exponent. In t years, when the account has been multiplied by 1.015 t times, the account value will be ...

  A = $700×1.015^t

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(b) You want to find t when A=$1200. Logarithms are involved.

  1200 = 700×1.015^t . . . . use 1200 for A

  1200/700 = 1.015^t . . . . . divide by 700

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Step-by-step explanation:

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Answer:  -p^2-(q+r)^2

Work Shown:

I'm assuming your teacher wants you to factor as much as possible.

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