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Svetlanka [38]
3 years ago
14

What is y=x-4;(-2,3)

Mathematics
1 answer:
Yuki888 [10]3 years ago
8 0

Answer:

3

Step-by-step explanation:

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Explain why the intercepts, on their own, cannot be used to graph the relation 5x+9y= 0.
goldfiish [28.3K]
5x + 9y = 0

to find the x int, sub in 0 for y and solve for x
5x + 9(0) = 0
5x = 0
x = 0

to find the y int, sub in 0 for x and solve for y
5(0) + 9y = 0
9y = 0
y = 0

the reason u cannot use just the intercepts is because the line goes through the origin (0,0)....The intercepts coincide giving u only 1 point...and that is not enough to graph a line
3 0
3 years ago
Simplify: 2cd3 (c- d+5)
sasho [114]

Answer:

2c2d3 − 2cd4 + 10cd3

hope it helps

6 0
3 years ago
When you have 6 significant numbers and want to get 9 what do you do
Leno4ka [110]
I think u add not sure though
8 0
4 years ago
Read 2 more answers
A motorboat takes 5 hours to travel 100mi going upstream. The return trip takes 2 hours going downstream. What is the rate of th
Temka [501]
The boat went 5hours upstream, let's say it has a "still water" speed rate of "b", it went 100miles... however, going upstream is going against the current, let's say the current has a speed rate of "c"

so, when the boat was going up, it wasn't really going "b" fast, it was going " b - c " fast, because the current was eroding speed from it

now, when coming down, the return trip, well the length is the same, so the distance is also 100miles, it only took 2hrs though, because, the boat wasn't coming down  "b" fast, it was coming down " b + c " fast, because the current was adding speed to it, so it came down quicker

now, recall your d = rt, distance = rate * time

\bf \begin{array}{lccclll}
&distance&rate&time\\
&-----&-----&-----\\
upstream&100&b-c&5\\
downstream&100&b+c&2
\end{array}
\\\\\\
\begin{cases}
100=(b-c)5\\
\qquad \frac{100}{5}=b-c\\
\qquad 20=b-c\\
\qquad 20+c=\boxed{b}\\
100=(b+c)2\\
\qquad 50=b+c\\
\qquad 50=\boxed{20+c}+c
\end{cases}

solve for "c", to see what's the current's speed

what's "b"?  well 20+c = b
4 0
3 years ago
In the given figure, find m∠RST, if m∠RSU = 43º and m∠UST = 23º.
pickupchik [31]

Applying the angle addition postulate, the measure of angle RST is: 66°.

<h3>What is the Angle Addition Postulate?</h3>

If two angles share a common vertex and a common side, they are adjacent angles that form a larger angle. According to the angle addition postulate, the sum of these two adjacent angles will give a sum that is equal to the measure of the larger angle they both form.

We know the following:

Measure of angle RSU = 43º

Measure of angle UST = 23º

In the diagram given, angle RSU and angle UST are adjacent angles that form a larger angle, angle RST.

Therefore, based on the angle addition postulate, the measure of angle RST = sum of the measures of angles RSU and UST.

Therefore, we would have:

m∠RST = m∠RSU + m∠UST

Substitute

m∠RST = 43 + 23

m∠RST = 66°

Learn more about the angle addition postulate on:

brainly.com/question/24746945

#SPJ1

8 0
1 year ago
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