An expression that can only provide a single solution, y,
for any given input, x, is called a “function”.
The given pairs are in the form (x,y)
Looking at set A:
(4,-2), (-2, 2), (2,-2), (4, 2)
Notice that if x=2, there are 2 y’s, -2 and 2. Therefore this
set is not a function.
<span>Answer: A is not a
function</span>
Answer:
d. 3
Step-by-step explanation:
hope this helps!!!!!!!<3
Hey there! Hello!
I believe what this question (more of a statement) is asking is to identify what a letter that represents an unknown number is called. Most of the time, i refer to it as just a variable, or an unknown variable. It can also be referred to as just an unknown value.
Feel free to ask me any additional questions if you have any! :-)
We know that if we had
8/6=2/2 times 4/3=1 times 4/3=4/3
find common factors in top and obttom
factor
48a^4-16a^2-32=(16)(a-1)(a+1)(3a^2+2)
8a^2-8=8(a-1)(a+1)
so we have
![\frac{48a^4-16a^2-32}{8a^2-8} = \frac{(2)(8)(a-1)(a+1)(3a^2+2)}{(8)(a-1)(a+1)}= (\frac{8}{8}) (\frac{a-1}{a-1})( \frac{a+1}{a+1}) ( \frac{(2)(3a^{2}+2)}{1})=](https://tex.z-dn.net/?f=%20%5Cfrac%7B48a%5E4-16a%5E2-32%7D%7B8a%5E2-8%7D%20%3D%20%5Cfrac%7B%282%29%288%29%28a-1%29%28a%2B1%29%283a%5E2%2B2%29%7D%7B%288%29%28a-1%29%28a%2B1%29%7D%3D%20%28%5Cfrac%7B8%7D%7B8%7D%29%20%28%5Cfrac%7Ba-1%7D%7Ba-1%7D%29%28%20%5Cfrac%7Ba%2B1%7D%7Ba%2B1%7D%29%20%28%20%5Cfrac%7B%282%29%283a%5E%7B2%7D%2B2%29%7D%7B1%7D%29%3D%20%20%20%20)
(2)(3a^2+2)=6a^2+4
answer is 6a^2+4