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marshall27 [118]
3 years ago
8

Solve each inequality. Then graph the solution.

Mathematics
2 answers:
zepelin [54]3 years ago
5 0

Answer:

Uh i have no idea

Step-by-step explanation:

Kay [80]3 years ago
4 0

Answer:

The first one is an open circle at -2 going right.

The second one is a closed circle at -2 going left.

The third one an open circle at -1.5 going left.

Step-by-step explanation:

I hope the helped :)

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The tensile strength of stainless steel produced by a plant has been stable for a long time with a mean of 72 kg/mm2 and a stand
Elanso [62]

Answer:

95% confidence interval for the mean of tensile strength after the machine was adjusted is [73.68 kg/mm2 , 74.88 kg/mm2].

Yes, this data suggest that the tensile strength was changed after the adjustment.

Step-by-step explanation:

We are given that the tensile strength of stainless steel produced by a plant has been stable for a long time with a mean of 72 kg/mm 2 and a standard deviation of 2.15.

A machine was recently adjusted and a sample of 50 items were taken to determine if the mean tensile strength has changed. The mean of this sample is 74.28. Assume that the standard deviation did not change because of the adjustment to the machine.

Firstly, the pivotal quantity for 95% confidence interval for the population mean is given by;

                         P.Q. = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean strength of 50 items = 74.28

            \sigma = population standard deviation = 2.15

            n = sample of items = 50

            \mu = population mean tensile strength after machine was adjusted

<em>Here for constructing 95% confidence interval we have used One-sample z test statistics as we know about population standard deviation.</em>

So, 95% confidence interval for the population mean, \mu is ;

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level of

                                                  significance are -1.96 & 1.96}  

P(-1.96 < \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } < 1.96) = 0.95

P( -1.96 \times {\frac{\sigma}{\sqrt{n} } } < {\bar X-\mu} < 1.96 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.95

P( \bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } } < \mu < \bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.95

<u><em>95% confidence interval for</em></u> \mu = [ \bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } } , \bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } } ]

                 = [ 74.28-1.96 \times {\frac{2.15}{\sqrt{50} } } , 74.28+1.96 \times {\frac{2.15}{\sqrt{50} } } ]

                 = [73.68 kg/mm2 , 74.88 kg/mm2]

Therefore, 95% confidence interval for the mean of tensile strength after the machine was adjusted is [73.68 kg/mm2 , 74.88 kg/mm2].

<em>Yes, this data suggest that the tensile strength was changed after the adjustment as earlier the mean tensile strength was 72 kg/mm2 and now the mean strength lies between 73.68 kg/mm2 and 74.88 kg/mm2 after adjustment.</em>

8 0
3 years ago
Suppose that 10 &lt; n &lt; 11. A possible value for n is
-BARSIC- [3]
★ Inequalities ★

10 < n < 11 \\
or n ∈ ( 10 , 11 )
Possible value can be easily obtained by generating an arithmetic mean

n = \frac{10 + 11}{2}  = 10.5
Else we've infinite numbers between them ,
According to density property of real numbers , we can have any real number satisfying the given inequality under condition 10 < n < 11
Which is true for infinite possible numbers
10.1 , 10.2 , ... INFINITY
8 0
3 years ago
Ricky has 3/4 of a bag of Skittles. He wants to split the rest between between his 5 friends. What fraction of the bag will each
Wittaler [7]

Answer:

  • 3/20, with the assumptions below.

Explanation:

The question seems incomplete.

In order to show you the procedure, I make some assumptions.

Assuming that Ricky wants to split the full content of the 3/4 of a bag between his 5 friends, to find what fraction of the bag will each friend receive you must divide 3/4 by 5.

The operation is:

        \dfrac{3}{4}\div 5

Convert the whole number 5 into fraction using 1 as denominator:

       \dfrac{3}{4}\div \dfrac{5}{1}

Transform the division into multiplication changing the divisor into its reciprocal:

       \dfrac{3}{4}\times \dfrac{1}{5}

Multiply numerator with numerator and denominator with denominator:

       \dfrac{3\times 1}{4\times 5}=\dfrac{3}{20}\leftarrow answer

7 0
3 years ago
Which is equivalent to sqrt 180x^11 after it has been simplified completely?
lorasvet [3.4K]

Answer:

180x^5.5

Step-by-step explanation:

6 0
2 years ago
THIS IS DUE IN 10 MIN!!
AVprozaik [17]
The discount is 50-14 = $36

% discount = (36/50)*100 = 72%
6 0
3 years ago
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