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marshall27 [118]
3 years ago
8

Solve each inequality. Then graph the solution.

Mathematics
2 answers:
zepelin [54]3 years ago
5 0

Answer:

Uh i have no idea

Step-by-step explanation:

Kay [80]3 years ago
4 0

Answer:

The first one is an open circle at -2 going right.

The second one is a closed circle at -2 going left.

The third one an open circle at -1.5 going left.

Step-by-step explanation:

I hope the helped :)

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How to solve for x 2+9x^2=6
juin [17]

Answer:

The answer is : 2/3

Step-by-step explanation:

2+9x^2=6

9x^2 = 6 - 2

9x^2 = 4

x^2 = 4/9

x = √(4/9)

x = 2/3

4 0
3 years ago
As a membership fee a health club charges a one time amount of $40 and charges $25 for each month. The total fee after m months
ICE Princess25 [194]
First you need to set up an equation y = mx + b. m would be the monthly charge and b would be the one time fee. x represents the number of months.
To solve for the number of months with a total price of 240 we substitute 240 in for y and solve for x.
240 = 25x + 40
subtract 40 from each side
200= 25x
divide by 25
8 = x
8 months

10 + 7r = 45
7r = 35
r = 5
5 miles
3 0
3 years ago
What the answer is to question number 4
cestrela7 [59]
Hey there!
The answer is D. 1/5
An explanation is in the attached image below.
Hope this helps!

3 0
3 years ago
What could the dimensions of a rectangle with an area of 48 inches be?
Dvinal [7]
To find an area of a rectangle, we use this method: A = lw (length x width)

We need to replace a(rea) with 48.

48 = lw.

The following expressions can be used:

1 x 48.

2 x 24.

3 x 16.

4 x 12.

6 x 8.

8 x 6.

12 x 4.

16 x 3.

24 x 2.

48 x 1.
6 0
2 years ago
The Town of Hertfordshire clerk knows that 23% of dogs in the town have completed emotional support training. Hertfordshire plan
Nataly_w [17]

Answer:

95.64% probability that under 30% of the dogs are emotional support trained

Step-by-step explanation:

For each dog, there are only two possible outcomes. Either they have completed emotional support training, or they have not. So we use the binomial probability distribution to solve this problem.

However, we are working with samples that are considerably big. So i am going to aproximate this binomial distribution to the normal.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

\mu = E(X) = np = 100*0.23 = 23

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{100*0.23*0.77} = 4.21

What is the probability that under 30% of the dogs are emotional support trained?

30% of 100 is 0.3*100 = 30

So this is the pvalue of Z when X = 30.

Z = \frac{X - \mu}{\sigma}

Z = \frac{30 - 23}{4.1}

Z = 1.71

Z = 1.71 has a pvalue of 0.9564.

So there is a 95.64% probability that under 30% of the dogs are emotional support trained

5 0
3 years ago
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