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3 years ago

6

What is the greatest common factor of 42 70 and 84

1 answer:

Delvig [45]3 years ago

7 0

The greatest common factor would be 14

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Find the sum<br> -2+(-3) =

viva [34]

Answer:

-5

Step-by-step explanation:

-2+(-3)

-2-3

-5

5 0

3 years ago

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Of 1000 randomly selected cases of lung cancer, 823 resulted in death within 10 years.

Arada [10]

Answer:

a) $0.823 - 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.799$

$0.823 + 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.847$

The 95% confidence interval would be given by (0.799;0.847)

b) $n=\frac{0.823(1-0.823)}{(\frac{0.03}{1.96})^2}=621.79$

And rounded up we have that n=622

c) $n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11$

And rounded up we have that n=1068

Step-by-step explanation:

Part a

$\hat p=\frac{823}{1000}=0.823$

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by:

$z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96$

The confidence interval for the mean is given by the following formula:

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$

If we replace the values obtained we got:

$0.823 - 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.799$

$0.823 + 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.847$

The 95% confidence interval would be given by (0.799;0.847)

Part b

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =\pm 0.03$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

And replacing into equation (b) the values from part a we got:

$n=\frac{0.823(1-0.823)}{(\frac{0.03}{1.96})^2}=621.79$

And rounded up we have that n=622

Part c

$n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11$

And rounded up we have that n=1068

5 0

3 years ago

Factor the trinomial and enter the factorization below. Write each factor as a

asambeis [7]

Answer:

(X+10)(X-3)

Step-by-step explanation:

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3 years ago

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How many cartons of nails should be purchased to shingle the roof shown in the illustration below?

Natalka [10]

How many cartons of nails it takes to shingle a roof duh

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3 years ago

The sum of the squares of two consecutive integers is 145. Find the two integers.

worty [1.4K]

Answer: The two integers are 8 and 9.

Step-by-step explanation: Let n represent the number.

n^2 + (n + 1)^2 = 145

By foiling, this can be rearranged to:

n^2 + n^2 + 2n + 1 = 145

Subtract 145 from both sides:

2n^2 + 2n - 144 = 0

Divide both sides by 2:

n^2 + n - 72 = 0

Factor the polynomial:

(n + 9)(n - 8) = 0

Solve for n:

n = -9, n = 8

Since they need to be consecutive, make the 9 positive. It will be positive either way because it is being squared.

Now, n = 9 and n = 8.

These are your two integers. Hope this helps!

6 0

3 years ago