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solong [7]
3 years ago
6

What are the zeros of (x-2)(x^2-9)

Mathematics
1 answer:
WARRIOR [948]3 years ago
3 0
(x-2)(x^2-9)=0\iff x-2=0\ or\ x^2-9=0\\\\x-2=0\ \ \ \ |add\ 2\ to\ both\ sides\\\\\boxed{x=2}\\\\x^2-9=0\ \ \ \ |add\ 9\ to\ both\ sides\\\\x^2=9\iff x=\pm\sqrt9\to \boxed{x=-3\ or\ x=3}\\\\Answer:\boxed{x=-3\ or\ x=2\ or\ x=3}
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Answer:

115% of 75 is equivalent to 75 by 1.15 = 8.625 , This two are equivalent

Step-by-step explanation:

Given as :

Tyson multiplies 75 by 1.15

I .e 75 × 1.15 = 86.25

Now A ) 115% of 75 = \frac{115}{100} × 75 = 86.25

B) 15% of 75 = \frac{15}{100}  × 75 = 11.25

C) 11.5% of 75 = \frac{11.5}{100} × 75 = 8.625

D) 1.15% of 75 = \frac{1.15}{100} × 75 = 0.8625

∵ 115% of 75 is equivalent to 75 by 1.15   ,  so Tyson try to find the option A

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Step-by-step explanation:

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