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solong [7]
3 years ago
6

What are the zeros of (x-2)(x^2-9)

Mathematics
1 answer:
WARRIOR [948]3 years ago
3 0
(x-2)(x^2-9)=0\iff x-2=0\ or\ x^2-9=0\\\\x-2=0\ \ \ \ |add\ 2\ to\ both\ sides\\\\\boxed{x=2}\\\\x^2-9=0\ \ \ \ |add\ 9\ to\ both\ sides\\\\x^2=9\iff x=\pm\sqrt9\to \boxed{x=-3\ or\ x=3}\\\\Answer:\boxed{x=-3\ or\ x=2\ or\ x=3}
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Write <br> 9 3/5<br> as an improper fraction.
Natalka [10]
48/5

9x5+3 divide by 5

45+3 divide by 5

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5 0
3 years ago
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Axis of symmetry of f(x)=(x+3)^2-8
Anna007 [38]

<u>ANSWER</u>

x =  - 3

<u>EXPLANATION</u>

When a quadratic equation is in the vertex form,

f(x) = a {(x - h)}^{2}  + k

the equation of axis of symmetry is simply

x = h

The given quadratic equation is

f(x) =  {(x + 3)}^{2}  - 8

We can rewrite this as

f(x) =  {(x  -  -  3)}^{2}  - 8

We now compare to

f(x) = a {(x - h)}^{2}  + k

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h =  - 3 \:  \:  \: and \:  \: k =  - 8

Therefore equation of axis of symmetry is:

x =  - 3

7 0
3 years ago
I need help with this equation pls help me
nataly862011 [7]

Answer:

x = 7\sqrt{3}

Step-by-step explanation:

8 0
3 years ago
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In this activity, you’ll create and interpret parts of linear and exponential expressions. Part A Write an expression with four
Ainat [17]

Four terms means four products, which are added up.

One term with an exponent:  2x^4

One term with a coefficient of five, let's make it a like term: 5x^4

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One constant: 7

Our expression:

2x^4 + 5x^4 + abx + 7


7 0
3 years ago
Imagine you have a pair of six-sided dice. What's the
Ksivusya [100]

Answer:

The  probability of rolling a seven or rolling an even number  as the sum of the two dice is \frac{2}{3}    

Step-by-step explanation:

Given : Imagine you have a pair of six-sided dice.

To find : What's the  probability of rolling a seven or rolling an even number  as the sum of the two dice?

Solution :

Rolling a pair of six-sided dice,

(1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6)

(2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)

(3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6)

(4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)

(5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6)

(6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)

Rolling a seven as the sum of the two dice are (1,6),(2,5),(3,4),(4,3),(5,2),(6,1)

Rolling an even number  as the sum of the two dice are (1,1),(1,3),(1, 5),(2, 2),(2, 4),(2, 6) ,(3, 1),(3, 3),(3, 5),(4, 2),(4, 4),(4, 6),(5, 1),(5, 3),(5, 5),(6, 2),(6, 4),(6, 6).

Favorable outcome of rolling a seven or rolling an even number  as the sum of the two dice are (1,6),(2,5),(3,4),(4,3),(5,2),(6,1), (1,1),(1,3),(1, 5),(2, 2),(2, 4),(2, 6) ,(3, 1),(3, 3),(3, 5),(4, 2),(4, 4),(4, 6),(5, 1),(5, 3),(5, 5),(6, 2),(6, 4),(6, 6) - 24

The probability is given by,

\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total outcome}}

\text{Probability}=\frac{24}{36}

\text{Probability}=\frac{2}{3}

Therefore, the  probability of rolling a seven or rolling an even number  as the sum of the two dice is \frac{2}{3}

5 0
3 years ago
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