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solong [7]
2 years ago
6

What are the zeros of (x-2)(x^2-9)

Mathematics
1 answer:
WARRIOR [948]2 years ago
3 0
(x-2)(x^2-9)=0\iff x-2=0\ or\ x^2-9=0\\\\x-2=0\ \ \ \ |add\ 2\ to\ both\ sides\\\\\boxed{x=2}\\\\x^2-9=0\ \ \ \ |add\ 9\ to\ both\ sides\\\\x^2=9\iff x=\pm\sqrt9\to \boxed{x=-3\ or\ x=3}\\\\Answer:\boxed{x=-3\ or\ x=2\ or\ x=3}
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Answer:

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Step-by-step explanation:

The triangle above is an isosceles triangle, In an Isosceles triangle the two angles; B and C are the same, hence the two sides; AB and AC are also the same.

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which implies;

2x = 3x - 7

subtract 3x from both-side of the equation

2x - 3x = 3x -3x -7

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Multiply through by -1

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But we were ask to find the the length of the line segment AC

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substituting x = 7 into the above equation will yield;

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