Question

Axis of symmetry of f(x)=(x+3)^2-8

Answer 1

ANSWER

$x = - 3$

EXPLANATION

When a quadratic equation is in the vertex form,

$f(x) = a {(x - h)}^{2} + k$

the equation of axis of symmetry is simply

$x = h$

The given quadratic equation is

$f(x) = {(x + 3)}^{2} - 8$

We can rewrite this as

$f(x) = {(x - - 3)}^{2} - 8$

We now compare to

$f(x) = a {(x - h)}^{2} + k$

We have

$h = - 3 \: \: \: and \: \: k = - 8$

Therefore equation of axis of symmetry is:

$x = - 3$