HELP? What percent of 33 is 99? 30% 33.3% 200% 300%

A restaurant chef bought potatoes at four different stores. The table shows the amount of the potatoes she bought at each store

hichkok12 [17]

Answer:

The way to answer this question is to find out the price per pound potato by dividing the amount the restaurant chief paid by the number of pounds bought.

Your question lacks details on the pounds bought in the other stores so I will assume these figures and you can use it as a reference.

Restaurant B - 2 pounds

Restaurant C - 12 pounds

Restaurant D - 5 pounds

Price per pound

Restaurant A = 6.60/8

= $0.83

Restaurant B = 3.50/2

= $1.75

Restaurant C = 9.75/12

= $0.82

Restaurant D = 4.80/8

= $0.96

Restaurant C has the lowest price per pound for potatoes.

3 0

3 years ago

Solve each equation. Show all steps 4) -8(-6-5k)=-232

Lubov Fominskaja [6]

the answer is k=4.6. hope this helps

6 0

3 years ago

Special right triangles, solve for x, y and z

Alika [10]

Answer:

x=14

y=27

z=43

Step-by-step explanation:

hope it helps!

6 0

2 years ago

The sum of two integers is 627, and the larger number is 27 more than 7 times the smaller number. Find the two integers.

Alex777 [14]

Answer:

75 and 552 =627

Step-by-step explanation:

First=x

Second 7x+27

x+ 7x+27= 627

8x+27=627

8x=600

x=75

75*7+27 =525

525+27 = 552

7 0

3 years ago

The students in Mr. Wilson's Physics class are making golf ball catapults. The

Mnenie [13.5K]

Answer:

Part a) About 48.6 feet

Part b) About 8.3 feet

Part c) The domain is $0 \leq x \leq 48.6\ ft$ and the range is $0 \leq y \leq 8.3\ ft$

Step-by-step explanation:

we have

$y=-0.014x^{2} +0.68x$

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

where

x is the ball's distance from the catapult in feet

y is the flight of the balls in feet

Part a) How far did the ball fly?

Find the x-intercepts or the roots of the quadratic equation

Remember that

The x-intercept is the value of x when the value of y is equal to zero

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-0.014x^{2} +0.68x=0$

so

$a=-0.014\\b=0.68\\c=0$

substitute in the formula

$x=\frac{-0.68(+/-)\sqrt{0.68^{2}-4(-0.014)(0)}} {2(-0.014)}$

$x=\frac{-0.68(+/-)0.68} {(-0.028)}$

$x=\frac{-0.68(+)0.68} {(-0.028)}=0$

$x=\frac{-0.68(-)0.68} {(-0.028)}=48.6\ ft$

therefore

The ball flew about 48.6 feet

Part b) How high above the ground did the ball fly?

Find the maximum (vertex)

$y=-0.014x^{2} +0.68x$

Find out the derivative and equate to zero

$0=-0.028x +0.68$

Solve for x

$0.028x=0.68$

$x=24.3$

Alternative method

To determine the x-coordinate of the vertex, find out the midpoint between the x-intercepts

$x=(0+48.6)/2=24.3\ ft$

To determine the y-coordinate of the vertex substitute the value of x in the quadratic equation and solve for y

$y=-0.014(24.3)^{2} +0.68(24.3)$

$y=8.3\ ft$

the vertex is the point (24.3,8.3)

therefore

The ball flew above the ground about 8.3 feet

Part c) What is a reasonable domain and range for this function?

we know that

A reasonable domain is the distance between the two x-intercepts

so

$0 \leq x \leq 48.6\ ft$

All real numbers greater than or equal to 0 feet and less than or equal to 48.6 feet

A reasonable range is all real numbers greater than or equal to zero and less than or equal to the y-coordinate of the vertex

so

we have the interval -----> [0,8.3]

$0 \leq y \leq 8.3\ ft$

All real numbers greater than or equal to 0 feet and less than or equal to 8.3 feet

8 0

2 years ago