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Contact [7]
3 years ago
10

I need helpppp (10 points )

Mathematics
1 answer:
irga5000 [103]3 years ago
4 0

Answer:  The flagpole is about 22.3 feet tall.

This is roughly the size of a two story building, assuming each floor is 10 feet or so.

Since this height is under 25 ft, this flagpole is in compliance with the regulation.

=====================================================

Work Shown:

The horizontal leg of the triangle is 36 ft. This is the adjacent leg to the reference angle 25 degrees.

The vertical leg of the triangle is x-5.5, and this leg is the opposite side to the reference angle 25 degrees.

Use the tangent rule to connect the opposite and adjacent sides.

Solve for x.

tan(angle) = opposite/adjacent

tan(25) = (x-5.5)/36

36*tan(25) = x-5.5

x-5.5 = 36*tan(25)

x = 36*tan(25)+5.5

x = 22.28707569358

x = 22.3 ft is the approximate height of the flagpole

Make sure your calculator is in degree mode.

The height is not over 25 ft, so this flagpole meets the requirements.

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what is the equation of a line that passes through the points (0,5) and (4,8)? write the answer in slope-intercept form.
Sergio039 [100]

Answer:

<h2>y = 3/4x + 5</h2>

Step-by-step explanation:

The slope-intercept form:

y=mx+b

m - slope

b - y-intercept → (0, b)

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points (4, 8) and (0, 5) → b = 5.

Calculate the slope:

m=\dfrac{5-8}{0-4}=\dfrac{-3}{-4}=\dfrac{3}{4}

Therefore we have the equation of the line:

y=\dfrac{3}{4}x+5

4 0
3 years ago
Read 2 more answers
One hour on earth is four hours on planet S.
Andreas93 [3]

Answer:

The answer is 60 hours.

Step-by-step explanation:

We could use proportions to solve.

\frac{1 \: hour \: on \: earth}{4hours \: on \: planet \: s}  =  \frac{x}{240hours \:  on \: planet  \: s}

4 \times x = 4x \\ 1 \times 240 = 240

\frac{4x}{4}  =  \frac{240}{4}  \\ x = 60

3 0
3 years ago
Use the elimination method to find all solutions of the system:
weqwewe [10]

Answer:

x = 3    and    y = 4

Step-by-step explanation:

Given

[Correct Question]

x^2 - 2y = 1

x^2 + 5y = 29

Required

Solve using elimination

First, we eliminate x.

Subtract equation (1) from (2)

x^2 - x^2 + 5y - (-2y) = 29 - 1\\

5y - (-2y) = 28

5y +2y = 28

7y = 28

Divide through ny 7

y = 4

Take x^2 - 2y = 1

Make x^2 the subject

x^2 = 1 + 2y

Substitute 4 for y

x^2 = 1 + 2*4

x^2 = 1 + 8

x^2 = 9

Take square roots

x = \sqrt 9

x = 3

7 0
2 years ago
Find the simultaneous equation x-2y=1,y^2-3xy+8=0​
Hitman42 [59]

Answer:

  (-2.2, -1.6), (3, 1)

Step-by-step explanation:

You don't have to go far to find the equations. They are right there in your problem statement. Perhaps you want to find the solutions to the equations.

Use the first equation to write an expression for x, then substitute that into the second equation:

  x = 2y +1

  y^2 -3(2y+1)(y) +8 = 0

  -5y^2 -3y +8 = 0

  -(5y +8)(y -1) = 0

  y = -8/5   or   y = 1

The corresponding values of x are ...

  x = 2(-8/5)+1 = -11/5

  x = 2(1) +1 = 3

The solutions are (x, y) = (-2.2, -1.6) and (3, 1).

5 0
2 years ago
What is 6.729 x 8.3 (show ur work)
katen-ka-za [31]

Answer:92,817,765

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Starting with the ones digit of the bottom number, the multiplier, multiply it by the last digit in the top number

Write the answer below the equals line

If that answer is greater than nine, write the ones place as the answer and carry the tens digit

Proceed right to left. Multiply the ones digit of the bottom number to the next digit to the left in the top number. If you carried a digit, add it to the result and write the answer below the equals line. If you need to carry again, do so.

When you've multiplied the ones digit by every digit in the top number, move to the tens digit in the bottom number.

Multiply as above, but this time write your answers in a new row, shifted one digit place to the left.

When you finish multiplying, draw another answer line below your last row of answer numbers.

Use long addition to add your number columns from right to left, carrying as you normally do for long addition.

Long Multiplication with Decimals

Long multiplication with decimals using the standard algorithm has a few simple additional rules to follow.

Count the total number of decimal places contained in both the multiplicand and the multiplier.

Ignore the decimals and right align the numbers one on top of the other as if they were integers

Multiply the numbers using long multiplication.

Insert a decimal point in the product so it has the same number of decimal places equal to the total from step 1.

4 0
2 years ago
Read 2 more answers
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