Ratio=2 ft/s
ratio=2 ft/s * (1 mile / 5280 ft)*(3600 s / 1 h)=1.36363636.. miles/h≈1.36 miles/h.
Answer: 1.36 miles/h
Answer:
37
Step-by-step explanation:
Answer:
The range of this function is {-13, -1, 15}.
Step-by-step explanation:
Evaluate f(x) = 4x - 1 at {-3, 0, 4}:
f(-3) = -13
f(0) = -1
f(4) = 15
The range of this function is {-13, -1, 15}.
The mean of the given sample data is 210, and the standard deviation is 7.937.
Given size 'n' = 300
The population proportion 'p' = 0.7
Let 'x' be the random variable of the binomial distribution
a) mean of the binomial distribution = n p = 300 × 0.7
μ = 210
b) variance of the binomial distribution
⇒ n p q
⇒ 300 × 0.7 ×0.3
⇒ σ² = 63
The standard deviation of the binomial distribution:
⇒ √n p q = √63 = 7.937
Thus, the mean of the given sample data is 210, and the standard deviation is 7.937.
Learn more about the standard deviation here:
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The question seems to be incomplete the correct question would be:
describe the sampling of p hat. Assume that the size of the population is 25000 n= 300 p=0.7 a) Determine the mean of the sampling distributionb) Dtermine the standard deviation of the sampling distribution
Answer:
The proportion of temperatures that lie within the given limits are 10.24%
Step-by-step explanation:
Solution:-
- Let X be a random variable that denotes the average city temperatures in the month of August.
- The random variable X is normally distributed with parameters:
mean ( u ) = 21.25
standard deviation ( σ ) = 2
- Express the distribution of X:
X ~ Norm ( u , σ^2 )
X ~ Norm ( 21.25 , 2^2 )
- We are to evaluate the proportion of set of temperatures in the month of august that lies between 23.71 degrees Celsius and 26.17 degrees Celsius :
P ( 23.71 < X < 26.17 )
- We will standardize our limits i.e compute the Z-score values:
P ( (x1 - u) / σ < Z < (x2 - u) / σ )
P ( (23.71 - 21.25) / 2 < Z < (26.17 - 21.25) / 2 )
P ( 1.23 < Z < 2.46 ).
- Now use the standard normal distribution tables:
P ( 1.23 < Z < 2.46 ) = 0.1024
- The proportion of temperatures that lie within the given limits are 10.24%
