Answer:
about 8.2 cm
Step-by-step explanation:
The key is to realize that the volume never changes.
The formula for the volume of a sphere is (4/3)*pi*radius^3
22/7 is being substituted in place of pi in this problem
The volume of one of the small spheres is
(4/3)*(22/7)*2^3 is about 33.524 cm^3
64 of those spheres would have a volume of 33.524*64, or about 2145 cm^3
Now, the problem is to find a sphere with a volume of 2145 cm^3
Volume = (4/3)*(22/7)*radius^3
plug in and solve
2145 = 4.1905*r^3
r^3=511.87
r is about equal to 8.2 centimeters
Pop ok you see so the answer here would be frantically elastic
|a+bi| = √(a² + b²)
-4-√2 i -> take a = -4 and b = -√2
|-4-√2 i| = √[ (-4)² + (<span>-√2)² ]
= </span><span>√[ 16 + 2<span> ]
</span></span><span>= √[ 18 ]</span> = <span>√[ 9 * 2 ]
= 3√2
the absolute value is 3√2</span>
