Write the equation of a line with that passes through the
points (-3, -2) and (6,1)?
1 answer:
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: Y = 1/3x - 1
:
M = y2 - y1/ x2-x1
M = 6 - (-3) / 1 - (-2)
Y = 1/3x + b
Then substitute one of the points into the equation
-2= 1/3(-3) + b
-2 + 2 + b = 1/3(-3) +b - b + 2
-b = 1/3(-3) + 2
-b = 1
b = -1
Y = 1/3x - 1
Then i plugged it into
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