Part A is irrational, but Parts B and C are both rational.
We know that Part A is irrational because an irrational number added to a rational number is still irrational. Also, an irrational number multiplied by a rational number is still irrational.
With Part B, we have an irrational number in the square root of 7. However, it is then squared to give us 7. This leaves us with 7 times a^2 which is rational. Two rational numbers multiplied still give us a rational number.
Finally, Part C only involves adding and multiplying rational numbers. Since that can only yield rational numbers, it must be rational.
Answer:
-15 + 10x
or
10x - 15
(either one works)
Step-by-step explanation:
You mean you just want me to expand it?
Ok.
Multiply -5 by 3 and -2x.
(-5)(3) = -15
(-5)(-2x) = +10x
Add those together:
-15 + 10x
or
10x - 15
Respuesta:
1/2; 4/3; 5/3; 1/4; 1/6; 4/7
Explicación paso a paso:
1.)
4/6 * 3/4
= 24/12
= 1/2
2.) 14/5 * 10/21
= 2/1 * 2/3
= 4/3
3.)
4/10 * 6/9
= 60/36
= 5/3
4.) 3/8 * 6/9
= 1/4 * 3/3
= 3/12 = 1/4
5.)
4/10 * 5/12
= 20/120
= 1/6
6.)
15/9 * 20/21
= 3/3 * 4/7
= 4/7
Answer:
(3,2)
Step-by-step explanation:
2x+3y=12
substitute x with 3 because x=3
2(3)+3y=12
multiply
6+3y=12
(subtract 6 from both sides)
3y=6
(divide by 3 on both sides)
1y=2
x = 3 and y = 2
Answer:
14
Step-by-step explanation:
A trapezoid is a quadrilateral (has four sides and four angles) with a pair of opposite parallel sides. The pair of opposite parallel side is known as the base.
An isosceles trapezoid is a trapezoid with equal legs. The diagonals are also equal and both the upper and lower base angles are congruent.
From the question:
KV = IE = 2x + 6 (diagonals of a trapezoid are congruent)
From line segment addition postulate:
KV = KN + NV
substituting:
2x + 6 = 10 + x
2x + 6 - x = 10
x + 6 = 10
x = 10 - 6
x = 4
KV = 2x + 6
substituting x = 4:
KV = 2(4) + 6
KV = 14