Answer:
set both of them equal to each other:
8x - 8° = 5x + 25°
subtract 5x by both sides of the equations and it becomes:
3x-8° = 25°
now add 8° both sides:
3x = 33°
divide three by both sides:
x = 11°
now thats done to find B:
plug your x value in the B equation:
5x + 25°
5(11) +25°
55 +25°
not sure if you can add here sorry :(. I hope this helped so far :)
The answer is 63/5ft long of the actual car. Hope this helps :)
Answer:
Its b!!!!!!
Step-by-step explanation:
Answer:
The range of T is a subspace of W.
Step-by-step explanation:
we have T:V→W
This is a linear transformation from V to W
we are required to prove that the range of T is a subspace of W
0 is a vector in range , u and v are two vectors in range T
T = T(V) = {T(v)║v∈V}
{w∈W≡v∈V such that T(w) = V}
T(0) = T(0ⁿ)
0 is Zero in V
0ⁿ is zero vector in W
T(V) is not an empty subset of W
w₁, w₂ ∈ T(v)
(v₁, v₂ ∈V)
from here we have that
T(v₁) = w₁
T(v₂) = w₂
t(v₁) + t(v₂) = w₁+w₂
v₁,v₂∈V
v₁+v₂∈V
with a scalar ∝
T(∝v) = ∝T(v)
such that
T(∝v) ∈T(v)
so we have that T(v) is a subspace of W. The range of T is a subspace of W.
