3 + 3 + 3 + + 4 + 4 =

Mathematics

2 answers:

Gennadij [26K]3 years ago

8 0

Answer:

3+3+3+3=12

4+4+4=12

Hope this helps

Scilla [17]3 years ago

4 0

Answer:

3 + 3 + 3 +3 =12

4 +4+4=12

Step-by-step explanation:

written in bord letters are answer

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Daniel [21]

Answer:

here (edit I made a mistake)

Step-by-step explanation:

9) $y=\frac{3}{5} x +5$

10) y = x - 3

11) $y=-\frac{3}{5} x - 3$

12) $y=\frac{5}{4} x + 2$

these are the slop int forms, my bad...

sorry

3 0

2 years ago

Read 2 more answers

Find sin(2x), cos(2x), and tan(2x) from the given information.

larisa86 [58]

Since $\cot(x)=\frac{2}{3}$ and $\cot^{2} x+1=\csc^{2} x$ , we know that:

$\left(\frac{2}{3} \right)^{2}+1=\csc^{2} x\\\\\frac{13}{9}=\csc^{2} x\\\\\csc x=\frac{\sqrt{13}}{3}$

If $\csc x=\frac{\sqrt{13}}{3}$ , this means that $\sin x=\frac{3}{\sqrt{13}}$ and by the Pythagorean identity,

$\sin^{2} x+\cos^{2} x=1\\\left(\frac{3}{\sqrt{13}} \right)^{2}+\cos^{2} x=1\\\frac{9}{13}+\cos^{2} x=1\\\cos^{2} x=\frac{4}13}\\\cos x=\frac{2}{\sqrt{13}}$

Using the double angle formula for sine, $\sin(2x)=2\left(\frac{3}{\sqrt{13}} \right)\left(\frac{2}{\sqrt{13}} \right)=\boxed{\frac{12}{13}}$
Using the double angle formula for cosine, $\cos(2x)=1-2\left(\frac{3}{\sqrt{13}} \right)^{2}=\boxed{-\frac{5}{13}}$
So, since tan=sin/cos, $\tan (2x)=\frac{\sin(2x)}{\cos(2x)}=\frac{\frac{12}{13}}{-\frac{5}{13}}=\boxed{-\frac{12}{5}}$