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3 years ago

6

a hiker in africa discovers a skull that contains 51% of its original amount of C-14. Find the of the scull to the nearest year

2 answers:

Kruka [31]3 years ago

8 0

Answer:

Actually it's 3285 for people on Plato.

Step-by-step explanation:

72%=100e^-.0001*t

Plug it into calculator.

you get 3285.04066972

Rounded that's 3285 years. Hope this helps?

Llana [10]3 years ago

6 0

We can calculate the age by using the formula: final amount=initial amount*(1/2)^(time/half-life), or t=ln(final amount/initial amount)/(-0.693)*half-life. The half life of C-14 is 5730 years, and final amount=initial amount is 51% or 0.51, so t=ln(0.51)/(-0.693)*5730=5567 years approximately.

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Step-by-step explanation:

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$P(A) = \frac{30}{100}$

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Step-by-step explanation:

Given

See attachment for proper format of table

$n = 100$ --- Sample

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Here, we only consider data in sample 1 row.

In this row:

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So, we have:

$n(A) = Yes + No$

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So, we have:

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So, we have:

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This is calculated as:

$P(A\ u\ B) = P(A) + P(B) - P(A\ n\ B)$

This gives:

$P(A\ u\ B) = \frac{30}{100} + \frac{77}{100} - \frac{22}{100}$

Take LCM

$P(A\ u\ B) = \frac{30+77-22}{100}$

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