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Mama L [17]
3 years ago
7

Please answer 1,2,3, and 4

Mathematics
1 answer:
Anika [276]3 years ago
5 0

Answer:

<u><em>1: "An equilateral triangle is never an obtuse triangle" & "An equilateral triangle is never an isosceles triangle." </em></u>

<u><em> </em></u>

<u><em>2: Acute Isosceles Triangle </em></u>

<u><em> </em></u>

<u><em>3: False! Option B. </em></u>

<u><em> </em></u>

<u><em>4: D</em></u>

Step-by-step explanation:

2: Isosceles Triangles have two equal sides. An acute triangle (or acute-angled triangle) is a triangle with three acute angles (less than 90°). An obtuse triangle (or obtuse-angled triangle) is a triangle with one obtuse angle (greater than 90°) and two acute angles.

3: An <u>equilateral triangle</u> is a triangle in which all the sides and all the angles are equal.

4: In order for a triangle to be <u>isosceles</u>, it has to have two same sides. For a triangle to be <u>equilateral</u>, all sides and angles need to be the same. Refer to reasoning in Question 2 for next explanation.

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b

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2 years ago
Page 1
scZoUnD [109]

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3 years ago
The given two-parameter family is a solution of the indicated differential equation on the interval
mr_godi [17]

Answer:

I do 1 option for you as an example, you need to check the leftover by yourself.

Step-by-step explanation:

for d) y(0) = 0 and y'(pi) =0

y(0) = C_1e^0cos(0)+ C_2 e^0 sin(0) = 0 \longrightarrow C_1 = 0

y(x) ' = C_1e^x cos(x) - C_1e^x sin (x) + C_2e^x sin(x) + C_2e^x cos(x)

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Replace C_1 = 0 we have

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if and only if C_2 =0

Hence the given solution does not work.

then, d is NOT the correct answer.

3 0
3 years ago
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