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3 years ago

In this scatter plot, there is a association between the variables ,

Mathematics

1 answer:

djyliett [7]3 years ago

6 0

Answer:strong

Step-by-step extplanation:

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Lynn multiplies 7/8 Times a number the product is less than 7/8 which could be Lynn's number

Brums [2.3K]

Answer: 6/8 <;3..?

Step-by-step explanation:

7 0

3 years ago

Isabella went into a movie theater and bought 3 drinks and 10 pretzels, costing a total of $54.50. Jason went into the same movi

ruslelena [56]

The price of 1 drink is $ 4 and price of 1 pretzel is $ 4.25

Solution:

Let d" be the price of 1 drink

Let "p" be the price of 1 pretzel

Given that, Isabella went into a movie theater and bought 3 drinks and 10 pretzels, costing a total of $54.50

Therefore, we can frame a equation as,

3 x price of 1 drink + 10 x price of 1 pretzel = 54.50

$3 \times d + 10 \times p = 54.50$

3d + 10p = 54.5 ---------- eqn 1

Jason went into the same movie theater and bought 9 drinks and 5 pretzels, costing a total of $57.25

9 x price of 1 drink + 5 x price of 1 pretzel = 57.25

$9 \times d + 5 \times p = 57.25$

9d + 5p = 57.25 ---------- eqn 2

Let us solve eqn 1 and eqn 2

Multiply eqn 1 by 3

9d + 30p = 163.5 ----- eqn 3

Subtract eqn 2 from eqn 3

9d + 30p = 163.5

9d + 5p = 57.25

( - ) -----------------------

25p = 106.25

p = 4.25

Substitute p = 4.25 in eqn 1

3d + 10(4.25) = 54.5

3d + 42.5 = 54.5

3d = 54.5 - 42.5

3d = 12

d = 4

Thus price of 1 drink is $ 4 and price of 1 pretzel is $ 4.25

4 0

3 years ago

Pleassssseeee help. I neeed help

xz_007 [3.2K]

Answer:

Step-by-step explanation:

Took the test :}

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3 years ago

Ln bisects klm into two congruent angles measuring (3x-4) and (4x-27) Find klm

blsea [12.9K]

The answer would be 135 (B)

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3 years ago

Element X decays radioactively with a half-life of eight minutes. If there are 800 g of element X, how long, to the nearest 10th

Harman [31]

Answer: 41.5 min

Step-by-step explanation:

This problem can be solved with the Radioactive Half Life Formula:

$A=A_{o}.2^{\frac{-t}{h}}$ (1)

Where:

$A=22 g$ is the final amount of the radioactive element

$A_{o}=800 g$ is the initial amount of the radioactive element

$t$ is the time elapsed

$h=8 min$ is the half life of the radioactive element

So, we need to substitute the given values and find $t$ from (1):

$22 g=(800 g) 2^{\frac{-t}{8 min}}$ (2)

$\frac{22 g}{800 g}=2^{\frac{-t}{8 min}}$ (3)

$\frac{11}{400}=2^{\frac{-t}{8 min}}$ (4)

Applying natural logarithm in both sides:

$ln(\frac{11}{400})=ln(2^{\frac{-t}{8 min}})$ (5)

$-3.593=-\frac{t}{8 min}ln(2)$ (6)

Clearing $t$ :

$t=41.46 min \approx 41.5 min$ This is the time elapsed

7 0

3 years ago