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Alex73 [517]
2 years ago
15

?????????????????????

Mathematics
1 answer:
anyanavicka [17]2 years ago
8 0

Answer:

It would be 1/8

Step-by-step explanation:

32 divided by 4 is 8

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In the illustration below, the three cube-shaped tanks are identical. The spheres in any given tank
fredd [130]

Answer:

1) Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) Amount \ of \, water \ remaining \ in \, the \ tank \ is \  \frac{x^3(6-\pi) }{6}

Step-by-step explanation:

1) Here we have;

First tank A

Volume of tank = x³

The  volume of the sphere = \frac{4}{3} \pi r^3

However, the diameter of the sphere = x therefore;

r = x/2 and the volume of the sphere is thus;

volume of the sphere = \frac{4}{3} \pi \frac{x^3}{8}= \frac{1}{6} \pi x^3

For tank B

Volume of tank = x³

The  volume of the spheres = 8 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 2·D = x therefore;

r = x/4 and the volume of the sphere is thus;

volume of the spheres = 8 \times \frac{4}{3} \pi (\frac{x}{4})^3= \frac{x^3 \times \pi }{6}

For tank C

Volume of tank = x³

The  volume of the spheres = 64 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 4·D = x therefore;

r = x/8 and the volume of the sphere is thus;

volume of the spheres = 64 \times \frac{4}{3} \pi (\frac{x}{8})^3= \frac{x^3 \times \pi }{6}

Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) For the 4th tank, we have;

number of spheres on side of the tank, n is given thus;

n³ = 512

∴ n = ∛512 = 8

Hence we have;

Volume of tank = x³

The  volume of the spheres = 512 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 8·D = x therefore;

r = x/16 and the volume of the sphere is thus;

volume of the spheres = 512\times \frac{4}{3} \pi (\frac{x}{16})^3= \frac{x^3 \times \pi }{6}

Amount of water remaining in the tank is given by the following expression;

Amount of water remaining in the tank = Volume of tank - volume of spheres

Amount of water remaining in the tank = x^3 - \frac{x^3 \times \pi }{6} = \frac{x^3(6-\pi) }{6}

Amount \ of \ water \, remaining \, in \, the \ tank =  \frac{x^3(6-\pi) }{6}.

5 0
3 years ago
Solve the proportion <img src="https://tex.z-dn.net/?f=%5Cfrac%7BX%2B1%7D%7B3%7D" id="TexFormula1" title="\frac{X+1}{3}" alt="\f
Ahat [919]
D.) 2 is the answer

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7 0
2 years ago
Express the relation {(-3, 4), (-1, 2), (3, -4), (2, -2)} as a table and a graph. What is the domain and range?
LuckyWell [14K]

Answer:

help

Step-by-step explanation:

please help please help please help please help please help first to asnwer gets brainleyist

2. Find the area of the parallelogram.

A.38cm

B.60cm

C.70cm

D.186cm

4 0
3 years ago
Read 2 more answers
Linear equation: -1
Anika [276]

Answer:

The right answer is:

the addition property of equality and then the division property of equality

Step-by-step explanation:

Given equation and steps to solve it are:

Step 1: –3x – 5 = 13

Step 2: –3x = 18

Step 3: x = –6

In step two, -5 has to be removed from left hand side of the equation so additional property of equality will be used i.e. adding 5 on both sides

Similarly in the third step, to remove -3 with x , division property of equality will be used i.e. dividing both sides by -3

Hence,

The right answer is:

the addition property of equality and then the division property of equality

6 0
3 years ago
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1<br> Find the value of x.<br> 117°<br> 1940<br> to
Artyom0805 [142]
The value of x is 83
8 0
2 years ago
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