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3 years ago

What the extreme point on the parabola

Mathematics

2 answers:

Darya [45]3 years ago

7 0

Answer:

Its Vertex dont listen to the clown above me

Step-by-step explanation:

ki77a [65]3 years ago

6 0

Answer:

Directrix

Step-by-step explanation:

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Ben and Josh went to the roof of their 40-foot tall high school to throw their math books offthe edge.The initial velocity of Be

Taya2010 [7]

Answer

Josh's textbook reached the ground first

Josh's textbook reached the ground first by a difference of $t=0.6482$

Step-by-step explanation:

Before we proceed let us re write correctly the height equation which in correct form reads:

$h(t)=-16t^2 +v_{o}t+s$ Eqn(1).

Where:

$h(t)$ : is the height range as a function of time

$v_{o}$ : is the initial velocity

$s$ : is the initial heightin feet and is given as 40 feet, thus Eqn(1). becomes:

$h(t)=-16t^2 + v_{o}t + 40$ Eqn(2).

Now let us use the given information and set up our equations for Ben and Josh.

Ben:

We know that $v_{o}=60ft/s$

Thus Eqn. (2) becomes:

$h(t)=-16t^2+60t+40$ Eqn.(3)

Josh:

We know that $v_{o}=48ft/s$

Thus Eqn. (2) becomes:

$h(t)=-16t^2+48t+40$ Eqn. (4).

Now since we want to find whose textbook reaches the ground first and by how many seconds we need to solve each equation (i.e. Eqns. (3) and (4)) at $h(t)=0$ . Now since both are quadratic equations we will solve one showing the full method which can be repeated for the other one.

Thus we have for Ben, Eqn. (3) gives:

$h(t)=0-16t^2+60t+40=0$

Using the quadratic expression to find the roots of the quadratic we have:

$t_{1,2}=\frac{-b+/-\sqrt{b^2-4ac} }{2a} \\t_{1,2}=\frac{-60+/-\sqrt{60^2-4(-16)(40)} }{2(-16)} \\t_{1,2}=\frac{-60+/-\sqrt{6160} }{-32} \\t_{1,2}=\frac{15+/-\sqrt{385} }{8}\\\\t_{1}=4.3276 sec\\t_{2}=-0.5776 sec$

Since time can only be positive we reject the $t_{2}$ solution and we keep that Ben's book took $t=4.3276$ seconds to reach the ground.

Similarly solving for Josh we obtain

$t_{1}=3.6794sec\\t_{2}=-0.6794sec$

Thus again we reject the negative and keep the positive solution, so Josh's book took $t=3.6794$ seconds to reach the ground.

Then we can find the difference between Ben and Josh times as

$t_{Ben}-t_{Josh}= 4.3276 - 3.6794 = 0.6482$

So to answer the original question:

Whose textbook reaches the ground first and by how many seconds?

Josh's textbook reached the ground first
Josh's textbook reached the ground first by a difference of $t=0.6482$

3 0

3 years ago

1. Congruent triangles are ______ similar

Afina-wow [57]

Similar triangles are Sometimes Similar

3 0

3 years ago

Please hurry. it's geometry.

Ainat [17]

That would be option A as the angles and sides ( the AS) have already been stated.

7 0

2 years ago

A family read the odometer before starting a trip .It read 22900.6 and they know they will be driving 302.5 miles . What's will

AlexFokin [52]

Answer:

23,203.1

Step-by-step explanation:

Generally, an odometer measures distance traveled during the usage life cycle of a car. It is necessary to say the distance is measured cumulatively.

Now, to get the value the odometer will be reading after the trip, we need to add the present reading of the odometer to the new distance to be traveled.

Thus, the reading of the odometer after the trip will be 22900.6 + 302.5 = 23,203.1

7 0

3 years ago

What is the slope of the line AB?

spayn [35]

Answer:

The slope of line AB is 2/1

Step by step explanation:

Hope this helps!!

6 0

3 years ago