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3 years ago

Hurry Asap Like Rn Pls I Will Give You Brainliest!

Mathematics

1 answer:

Rom4ik [11]3 years ago

5 0

Answer:

Step-by-step explanation:

Each package holds 24 so you would use the equation n = 24p

which means the number of lightbulbs = 24 times the number of packages

so 1 package = 24

3 packages = 72

10 packages = 240

oh and part B is B

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Need help as soon as possible

alukav5142 [94]

Answer:

D. 70

Step-by-step explanation:

if vx is bisector then 3z - 4 = z + 6 add like terms

2z = 10;and z = 5

To find the perimeter we add all side lengths

VU + UW + WV = 5z - 1 + 5z - 1 + 3z - 4 + z + 6 = 14z

we know z = 5 so 14 × 5 = 70

8 0

3 years ago

. Sabrina jogged 54 laps around the

-BARSIC- [3]

Answer:

B) 6 times

Step-by-step explanation:

54/9=6

5 0

4 years ago

Read 2 more answers

Kids bought a package with 2 9/ 16 lb of ground meat to make hamburgers he was he has 2/5 pound of ground meat left about how ma

poizon [28]

Answer:

The quantity of ground meat he use for hamburgers is 2 $\frac{13}{80}$ pounds

Step-by-step explanation:

Given as :

The total quantity of ground meat bought to make hamburgers = 2 $\frac{9}{16}$

Or, The total quantity of ground meat bought to make hamburgers = $\frac{41}{16}$ pound

The quantity of ground meat left after use = $\frac{2}{5}$ pound

Now, let The quantity of ground meat used for hamburgers = x pound

So, x = The total quantity of ground meat bought - The quantity of ground meat left

Or, x = $\frac{41}{16}$ pound - $\frac{2}{5}$ pound

Or, x = $\frac{205-32}{80}$ pound

I.e x = $\frac{173}{80}$

∴ x = 2 $\frac{13}{80}$ pounds

Hence The quantity of ground meat he use for hamburgers is 2 $\frac{13}{80}$ pounds . Answer

7 0

3 years ago

In a camp, 95 kg food is sufficient for 5 persons. Find the quantity of food required for 23 persons.

NNADVOKAT [17]

95/5= 19 (the rate; each person needs 19 kg of food)

So,

You need to multiply that by 23 to get the amount you need for 23 people.

19*23= 437 kg

437 kg is sufficient for 23 people.

I hope this helps!
~kaikers

3 0

3 years ago

Verifying Properties of logarithms In Exercise,use a graphing utility to verify that the functions are equivalent for x > 0.

Ede4ka [16]

Answer:

Applying Quotient and power rule. Graphically, for x>0 both curves coincide.

Step-by-step explanation:

1) Firstly, by applying the Quotient and then the Power Rule, we have a subtraction of the argument and, finally the exponent turns to be the coefficient. As it follows:

$lnx=log_{e}x\\\\f(x) = ln({\frac{x^{2}}{4}})\Rightarrow f(x)=ln{x^2}-ln4\Rightarrow f(x)=2lnx-ln4\\g(x) = 2 ln x - ln 4$

2) Check the graph below to see this equivalence. to see x>0 they both coincide.

7 0

3 years ago