Answer:
<h3>72 units</h3>
Step-by-step explanation:
Given D,E, and F are collinear points and E is between D and F, then the expression DE + EF = DF.... 1 is true
If DE is six times the length of EF, then;
DE = 6DF
DF = DE/6 .....2
Substitute equation 2 into 1;
DE + EF = DF
DE + DE/6 = DF
find the LCM
(6DE+DE)/6 = DF
cross multiply
6DE+DE = 6DF
7DE = 6DF
Given DF = 84units
7DE = 6(84)
7DE = 504
Divide both sides by 7
7DE/7 = 504/7
DE = 72
Hence the length of segment DE is 72units
Answer:
4.1 in
Step-by-step explanation:
now we multiply pi and 10.71- i left it in the hundreths
place when i get my final answer ill round it to the tenths)
, we need the 
alone so we now dive with 33. 62 on both sides, elimenating the 33.62. Now 751/ 33.62= 16.98.
now we square root it
= 4.12 which rounded is 4.1
Answer:
8.5 * 10^-3
Step-by-step explanation:
Answer: x=12
Step-by-step explanation:
