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Sonja [21]
3 years ago
12

Copper has a density of 8.9 g/cm A copper necklace has a volume of 396 cm”.

Mathematics
1 answer:
Leviafan [203]3 years ago
7 0

Answer:

3524.4 g

Step-by-step explanation:

  • Use formula: Density = Mass/Volume
  • Mass= Density * Volume

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Find the sum of the arithmetic sequence 22, 11, 0, -11, ..., –77.
blagie [28]

Answer:

B.

Step-by-step explanation:

First you need to figure out how many numbers there are, so with this you can simply count 10. Then use the formula to plug in the numbers: 10(22-77)/2 to get the answer.

7 0
4 years ago
Find the five-number summary for the data. {231, 201, 221, 210, 225, 228, 212, 236, 225, 201, 216, 215, 231, 226, 206, 240}
pshichka [43]

Answer:

201, 206, 216, 228, 240

Step-by-step explanation:

4 0
3 years ago
how does the appearence of a histogram change when u use many small intervals then when you use a few large intervals
vampirchik [111]
If you're using a few larger intervals, then your histogram looks more stocky. If you imagine drawing one, it's because you're adding more values into the same category which can make the difference between two intervals much more noticeable. If you're using smaller intervals, however, you can much more accurately assess the difference between two different intervals. For that reason, the transition between one and another interval would look much more 'fluid'.
5 0
3 years ago
Consider the population of all 1-gallon cans of dusty rose paint manufactured by a particular paint company. Suppose that a norm
Artemon [7]

Answer:

a) 0.5.

b) 0.8413

c) 0.8413

d) 0.6826

e) 0.9332

f) 1

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 6, \sigma = 0.2

(a) P(x > 6) =

This is 1 subtracted by the pvalue of Z when X = 6. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{6-6}{0.2}

Z = 0

Z = 0 has a pvalue of 0.5.

1 - 0.5 = 0.5.

(b) P(x < 6.2)=

This is the pvalue of Z when X = 6.2. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{6.2-6}{0.2}

Z = 1

Z = 1 has a pvalue of 0.8413

(c) P(x ≤ 6.2) =

In the normal distribution, the probability of an exact value, for example, P(X = 6.2), is always zero, which means that P(x ≤ 6.2) = P(x < 6.2) = 0.8413.

(d) P(5.8 < x < 6.2) =

This is the pvalue of Z when X = 6.2 subtracted by the pvalue of Z when X  5.8.

X = 6.2

Z = \frac{X - \mu}{\sigma}

Z = \frac{6.2-6}{0.2}

Z = 1

Z = 1 has a pvalue of 0.8413

X = 5.8

Z = \frac{X - \mu}{\sigma}

Z = \frac{5.8-6}{0.2}

Z = -1

Z = -1 has a pvalue of 0.1587

0.8413 - 0.1587 = 0.6826

(e) P(x > 5.7) =

This is 1 subtracted by the pvalue of Z when X = 5.7.

Z = \frac{X - \mu}{\sigma}

Z = \frac{5.8-6}{0.2}

Z = -1.5

Z = -1.5 has a pvalue of 0.0668

1 - 0.0668 = 0.9332

(f) P(x > 5) =

This is 1 subtracted by the pvalue of Z when X = 5.

Z = \frac{X - \mu}{\sigma}

Z = \frac{5-6}{0.2}

Z = -5

Z = -5 has a pvalue of 0.

1 - 0 = 1

5 0
3 years ago
Can someone please help me find the answer to #19? I attached a photo of the problem
brilliants [131]

Answer:

21 packages

Step-by-step explanation:

4 ÷3/16= 4 x 16= 64/3=21 1/3 .     21 packages

hope this helps :)

4 0
3 years ago
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