Remember the chain rule.
L(x)=f(g(x))
L'(x)=f'(g(x))g'(x)
take the derivative of f(g(x)). just treat them like they are variables. so you get:
h'=f'(g(x))g'(x)
now plug in your x value and evaluate:
h'(1)=f'(g(1))(g'(1))
substitute in values that you know and evaluate again
h'(1)=f'(3)(-3)
h'(1)=(-5)(-3)=15
<h3>

</h3>
Answer:
Solution given
Cos
consider Pythagorean theorem

Subtracting
both side

doing square root on both side we get

Similarly

Substituting value of 
we get

<h3>Solving numerical</h3>




Since
In IVquadrant sin angle is negative

3x² + 7x - 10
3x² - 3x + 10x - 10
3x(x) - 3x(1) + 10(x) - 10(1)
3x(x - 1) + 10(x - 1)
(3x + 10)(x - 1)
The answer is D.
A = 3
b = 6
c = 5
Hope this helps
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Step-by-step explanation:
5(2)^2 -2 -4
5(4)-6
20-6
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