Here we have a case of the least common multipl(lcm) of 6 and 20.
Prime numbers 2,3,5,7,11,13,17,19... (natural numbers greater than 1 that has no positive divisors other than 1 and itself) .
lcm(6,20)= 6 20 | 2
3 10 | 3
1 10 | 2
5 | 5
1
2*3*2*5=60 The first one to get both calendar and the animal toy will be 60th.
Explenation: First we look for the smallest prime number with wich 6 and 20 can be devided by. That is 2. Next is 3. Since 10 is not divisible by 3, we only copy it. Under the 6 we got 1, wich is our goal. Now we continue to devide 10 by prime numbers till we also get 1. We now multiple all divisors and we get the least common multiple.
Answer: You are smart, figure it out yourself
Step-by-step explanation:
Answer:
Step-by-step explanation:
<u>We know that:</u>
<u>Solution:</u>
- 34 + 4q = 90°
- => 4q = 90 - 34
- => 4q = 56
- => q = 56/4
- => q = 14
Hence, the value of q is 14.
Answer:
B
Step-by-step explanation:
For example, subtract 56 by 47, you get 9. Each term is 9 more than the previous term.
Here is the answer for the 1st one. I have a picture of the second one but I’m not sure if I can post the picture of it
